Question

Find the equation of a straight line that passes through the points(-2,10) and (4,14)​

Answer 1

Answer:

y = $\frac{2}{3}$x + 11$\frac{1}{3}$

Step-by-step explanation:

The equation of a straight line is: y = mx+c where m is the slope of the line and c is the y-intercept of a line.

Slope = $\frac{rise}{run}$

          = $\frac{14-10}{4-(-2)}$

          = $\frac{4}{6}$

          = $\frac{2}{3}$

To find the y-intercept, we can use one of the points to apply for the equation before finding the y-intercept. I will be using the point (4,14).

y = $\frac{2}{3}$x + c

14 = $\frac{2}{3}$×4 + c

14 = 2$\frac{2}{3}$ + c

c = 14-2$\frac{2}{3}$

c = 11$\frac{1}{3}$

Thus, the y-intercept is 11$\frac{1}{3}$.