Answer:
Can I please have more details on what your question is?
Step-by-step explanation:
Answer:
Here,
![2x + 4y = 16....eqn \: i \\ 4y = 12....eqn \: ii](https://tex.z-dn.net/?f=2x%20%2B%204y%20%3D%2016....eqn%20%5C%3A%20i%20%5C%5C%204y%20%3D%2012....eqn%20%5C%3A%20ii)
substituting the value of 4y in eqn i fron eqn ii
so eqn i becomes
![2x + 12 = 16 \\ 2x = 4 \\ x = 2](https://tex.z-dn.net/?f=2x%20%2B%2012%20%3D%2016%20%5C%5C%202x%20%3D%204%20%5C%5C%20x%20%3D%202)
So
![y = 12 \div 4 = 3](https://tex.z-dn.net/?f=y%20%3D%2012%20%5Cdiv%204%20%3D%203)
Thus,
![x = 2 \: and \: y = 3](https://tex.z-dn.net/?f=x%20%3D%202%20%5C%3A%20and%20%5C%3A%20y%20%3D%203)
...hope this helps:)
It will be 42 because of the with times the 2nd highest
Doubt --!!
Where is your question!??????