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3 years ago

Tammy's allowance is $5.00. She did extra chores around the house and earned an

Mathematics

2 answers:

ikadub [295]3 years ago

8 0

Answer:

5.50 this should help :p

scoray [572]3 years ago

7 0

5+1.75=6.75
6.75-2.25=4.50
4.50-1=5.50

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Moonshine Problem: How many gallons of 20% moonshine and how many gallons of 30% moonshine have to be mixed together to make 100

Sindrei [870]

Answer:

50 gallons 20%

50 gallons 30%

Step-by-step explanation:

If x is gallons of 20% moonshine, and y is gallons of 30% moonshine, then:

x + y = 100

0.20x + 0.30y = 0.25(100)

Solve the system of equations using substitution or elimination. Using substitution:

0.20x + 0.30(100 − x) = 0.25(100)

0.20x + 30 − 0.30x = 25

5 = 0.10x

x = 50

y = 50

3 0

4 years ago

Machine A and machine B both make car parts.

Klio2033 [76]

504+640=1144 hope this helps!

5 0

3 years ago

Solve the equation for all real solutions in the simplest form. -5z^2-3z-11=-6z^2

horsena [70]

Answer:

-3z-11=11z^2

Step-by-step explanation:

3 0

2 years ago

Jack and Jill live 126 km apart. They want to leave their homes at the same time,

Digiron [165]

Answer:

Both will leave their homes to meet on time at 9 am

Step-by-step explanation:

Given as, Distance between Jack and Jill = 126 km

Speed of Jack rides = 18 kilometers per hours

Speed of Jill rides = 24 kilometers per hours

Let the distance travel by Jack = x km

And the distance travel by Jill = (126 - x ) km

Time taken by Jack and Jill = T hours

Now , Distance = Speed × Time

So, x = 18 × T

And 126 - x = 24 × T

Or, 126 - x = 24 × $\frac{x}{18}$

Or, 126 - x = x × $\frac{4}{3}$

Or, 378 - 3x = 4x

Or, 378 = 7x

i.e x = $\frac{378}{7}$ = 54 km

And distance travel by Jill = 126 - 54 = 72 km

So, time taken by Jack = $\frac{x}{18}$ = $\frac{54}{18}$

Or, Time taken by Jack = 3 hours

Similarly Time take by Jill = $\frac{72}{24}$ = 3 hours

∵ Both Jack and Jill will take 3 hours to meet at 12 : 00 pm

Hence, Both will leave their homes to meet on time at 9 am Answer

7 0

4 years ago

Carbon-14 dating assumes that the carbon dioxide on Earth today has the same radioactive content as it did centuries ago. If thi

defon

7978 years

Step-by-step explanation:

A = A02^(-t/hl)

where hl = half-life.

Dividing both sides by A0 and taking the logarithm, we get

ln(A/A0) = -(t/hl)ln2

or solving for t,

t= -(hl)ln(A/A0)/ln2

note that A/A0 = 0.38

t = -(5715 yrs)[ln(0.38)/ln2]

= 7978 years

7 0

3 years ago