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Nadusha1986 [10]
3 years ago
7

Can someone please help me on this THIS IS URGENT!!!!

Mathematics
2 answers:
andre [41]3 years ago
7 0
What are we helping with
max2010maxim [7]3 years ago
5 0

Answer:

I can't answer this the picture doesn't have anything on it

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Find the value of x.<br> 105° /15xº
pogonyaev

Answer:

X=7

Step-by-step explanation:

I am so sorry if this is not correct. I don´t know why there are 0s next to each number. I hope this helped. Again, I am sorry if this is incorrect

8 0
3 years ago
Answers and step by step explanations please?(Just one example)​
Allushta [10]
Answer is 4x x 3y >e3£
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3 years ago
HELP! A daycare purchases two type of snacks, granola bars and fruit rolls. One week, they purchase 10 packs of granola bars and
ch4aika [34]
10x+6y=152
5x+3y=76
7x+12y=200
-20x-12y=-304
-13x=-104
x=8
40+3y=76
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y=12
There are 8 granola bars in a pack and 12 fruit rolls in a pack
5 0
3 years ago
Read 2 more answers
Please help! (Also show work)<br> Tutorials :D
oksano4ka [1.4K]

The five-number summary is:

Minimum: 9

First Quartile: 16.5

Median: 25.5

Third Quartile: 39

Maximum: 51

3. Range = 42

4. Interquartile range = 22.5

<h3>How to Find the Five-number Summary of a Data?</h3>

Given the data for the lengths as, 36, 15, 9, 22, 36, 14, 42, 45, 51, 29, 18, 20, to find the five-number summary of the data set, we would follow the steps below:

1. The numbers in ordered from the smallest to the largest would be:

9, 14, 15, 18, 20, 22, 29, 36, 36, 42, 45, 51

2. The five-number summary for the lengths in minutes would be:

  • Minimum value: this is the smallest lengths, which is 9
  • First Quartile (Q1): this is the middle of the first half of the data set of the lengths in minutes, which is 16.5.
  • Median: the median is the center of the data distribution which is 25.5.
  • Third Quartile: this is the middle of the second half of the data set of the lengths in minutes, which is 39.
  • Maximum: this is the largest length in minutes, which is, 51.

3. Range of the data = max - min = 51 - 9 = 42

4. The interquartile range for the data set = Q3 - Q1 = 39 - 16.5

Interquartile range for the data set = 22.5

Learn more about the five-number summary on:

brainly.com/question/24809873

#SPJ1

6 0
1 year ago
Divide 1.20m in the ratio 2:3:4
viktelen [127]
x = 1,2 : 9 =  \frac{2}{15} \\2x:3x:4x\\ \frac{4}{15} : \frac{2}5} : \frac{8}{15}
5 0
3 years ago
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