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3 years ago

1. Find the mean median and mode of the data set.

2 answers:

6 0

I think it C because the mean and median were originally 25 as median and 10.2 as mean and when the $15 were added the median was still 25 but the 10.2 was changed to a 11.7

Shtirlitz [24]3 years ago

6 0

1. mean) 4+10+3+1=18 18÷4=4.5 median) 1x,3,4,10x 3+4=7 7+1=8 8÷2=4 mode) there is no mode in the list as no values are repeated

2. mean before) 25+25+22+30=102 102÷4=25.5 mean after) 25+25+22+30+15=117 117÷4=29.25 median before) 22x,25,25,30x 25+25=50 50÷2=25 median after) 15x,22x,25,25x,30x

none of them. the mean increased and the median stayed the same.

I have underlined all my answers so it is easier for you to find them.

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The given line passes through the points (−3, 4) and (3, -4). What is the equation, in point-slope form.

lidiya [134]

We replace two point into any equation
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y-4=-4/3(x+3)
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7 0

3 years ago

What is the x and y intercept of 2.5x+8y=240 please show your work.

a_sh-v [17]

Answer:

The x and y intercept are (96,30)

Step-by-step explanation:

8y=240-2.5x

y=240/8-2.5x/8

y=30-0.3125x

The y intercept=30

The x intercept=96 thus 30=0.3125x,x=30/0.3125

5 0

3 years ago

WHat is derivative of x^x^x^x

kicyunya [14]

Answer:

The answer is 0

Step-by-step explanation:

Technically you didn't term x, so it would be a constant with respect to x

5 0

4 years ago

The perimeter of a retangular pool is 360 inches the length is 8 inches longer than the width find the dimensions of the pool

White raven [17]

360=2w+2l
l=8+w

Substitute for l
360=2w+2(8+w)
360=2w+16+2w
360=4w+16
344=4w
86=w

Plug in the w value
l=8+(86)
l=94

Final answer: Length-94 inches, Width-86 inches

4 0

3 years ago

2) The results of a 2012 Pew Foundation survey of high school and middle school teachers is given in the pie chart. A student as

Serggg [28]

Answer:

The calculated value z = 9.4451 > 1.96 at 5% level of significance.

Null hypothesis is rejected at 5% level of significance

yes there is difference in the distribution of types of cell phones for the teachers in 2018 at a 5% level of significance

Step-by-step explanation:

Explanation:-

Step:- (1)

The results of a 2012 Pew Foundation survey of high school and middle school teachers is given in the pie chart.

A student asked a random sample of teachers in 2018 and found 165 had smart-phones, 80 had a cell phone

The first sample proportion

$p_{1} = \frac{80}{165} = 0.4848$

A student asked a random sample of teachers in 2018 and found 165 had smart-phones,5 had no cell phone

The second sample proportion

$p_{2} = \frac{5}{165} = 0.03030$

Step :-(ii)

Null hypothesis :H₀: Assume that there is no difference in the distribution of types of cell phones for the teachers in 2018

H₀ : p₁ = p₂

Alternative hypothesis :H₁

H₁ : p₁ ≠ p₂

Level of significance : ∝=0.05

The tabulated value z=1.96

Step:-(iii)

The test statistic

$Z = \frac{p_{1} -p_{2} }{\sqrt{pq(\frac{1}{n_{1} } } +\frac{1}{n_{2} } )} }$

where $p = \frac{n_{1}p_{1} +n_{2} p_{2} }{n_{1} + n_{2} }$

q = 1-p

In given data n₁ = n₂ = n

$p = \frac{165 (0.4848)+165 (0.03030 }{165 + 165}$

on calculation , we get p = 0.2655

q =1-p = 1-0.2655

q = 0.7345

$Z = \frac{0.4848 -0.030}{\sqrt{0.2655X0.7345(\frac{1}{165 } } +\frac{1}{165} )} }$

Z = 9.4451

The calculated value z = 9.4451 > 1.96 at 5% level of significance.

Conclusion:-

Null hypothesis is rejected at 5% level of significance

yes there is difference in the distribution of types of cell phones for the teachers in 2018 at a 5% level of significance

6 0

4 years ago