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3 years ago

I need the answers to this ASAP

Mathematics

1 answer:

Doss [256]3 years ago

7 0

Answer:

First Answer: A = $ 4,247.03

A = P + I where

P (principal) = $ 4,000.00

I (interest) = $ 247.03

Second Answer : A = $ 6,325.22

A = P + I where

P (principal) = $ 5,500.00

I (interest) = $ 825.22

Third Answer: A = $ 7,735.55

A = P + I where

P (principal) = $ 7,000.00

I (interest) = $ 735.5

Fourth Answer: A = $ 7,735.55

A = P + I where

P (principal) = $ 7,000.00

I (interest) = $ 735.55

Step-by-step explanation:

HOPE IT HELPS MARK ME BRAINLIEST :)

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An elementary school is offering 3 language classes: one in Spanish, one in French,and one in German. The classes are open to an

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Answer:

A. 0.5

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Step-by-step explanation:

There are

28 students in the Spanish class,
26 in the French class,
16 in the German class,
12 students that are in both Spanish and French,
4 that are in both Spanish and German,
6 that are in both French and German,
2 students taking all 3 classes.

So,

2 students taking all 3 classes,
6 - 2 = 4 students are in French and German, bu are not in Spanish,
4 - 2 = 2 students are in Spanish and German, but are not in French,
12 - 2 = 10 students are in Spanish and French but are not in German,
16 - 2 - 4 - 2 = 8 students are only in German,
26 - 2 - 4 - 10 = 10 students are only in French,
28 - 2 - 2 - 10 = 14 students are only in Spanish.

In total, there are

2 + 4 + 2 + 10 + 8 + 10 +14 = 50 students.

The classes are open to any of the 100 students in the school, so

100 - 50 = 50 students are not in any of the languages classes.

A. If a student is chosen randomly, the probability that he or she is not in any of the language classes is

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B. If a student is chosen randomly, the probability that he or she is taking exactly one language class is

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C. If 2 students are chosen randomly, the probability that both are not taking any language classes is

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$1-0.25=0.75$

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