Answer:
The program in Python is as follows:
num1 = int(input())
num2 = int(input())
if num2 < num1:
print("Second integer can't be less than the first.")
else:
for i in range(num1,num2+1,5):
print(i,end=" ")
Explanation:
This gets the first integer from the user
num1 = int(input())
This gets the second integer from the user
num2 = int(input())
If the second is less than the first, the following prompt is printed
<em>if num2 < num1:</em>
<em> print("Second integer can't be less than the first.")</em>
If otherwise, the number between the intervals is printed with an increment of 5
<em>else:</em>
<em> for i in range(num1,num2+1,5):</em>
<em> print(i,end=" ")</em>
<em />
The recursive function would work like this: the n-th odd number is 2n-1. With each iteration, we return the sum of 2n-1 and the sum of the first n-1 odd numbers. The break case is when we have the sum of the first odd number, which is 1, and we return 1.
int recursiveOddSum(int n) {
if(2n-1==1) return 1;
return (2n-1) + recursiveOddSum(n-1);
}
To prove the correctness of this algorithm by induction, we start from the base case as usual:
by definition of the break case, and 1 is indeed the sum of the first odd number (it is a degenerate sum of only one term).
Now we can assume that 
returns indeed the sum of the first n-1 odd numbers, and we have to proof that 
returns the sum of the first n odd numbers. By the recursive logic, we have
and by induction, is the sum of the first n-1 odd numbers, and 2n-1 is the n-th odd number. So, is the sum of the first n odd numbers, as required:
In my opinion, I would say No. So I think the answer is C.
The statement, "The amount of magnification gained from the extension tube is dependent on the focal length of the lens" is true.
A Human-Machine Interface (HMI) is a graphic terminal that allows the robot operator to control, monitor, and collect data from the robot system.
(https://www.robots.com/faq/what-is-a-hmi)
