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PSYCHO15rus [73]
3 years ago
5

What is it called when you remove some information from a file or remove a file from the disk ? A) save b) delete c) edit d) rem

ove
Computers and Technology
1 answer:
Kamila [148]3 years ago
3 0

Answer:

delete is the answer okkkkkkkkkkkkkkkk

You might be interested in
The function below takes two numeric parameters. The first parameter specifies the number of hours a person worked and the secon
Triss [41]

Answer:

def calculate_pay(total_worked_hours, rate_per_hour):

   if total_worked_hours > 40:

       return (40 * rate_per_hour) + ((total_worked_hours - 40) * 2 * rate_per_hour)

   else:

       return total_worked_hours * rate_per_hour

Explanation:

  • Create the calculate_pay function that takes 2 parameters.
  • Inside the function check whether the total_worked_hours is greater than 40 and then return the pay by calculating with the help of formula for work over 40 hours.
  • Otherwise return the pay by multiplying the total_worked_hours with rate_per_hour.
6 0
4 years ago
Ayuda pliz es para ya!!!!!<br> nesesito un codigo html que me muestre este texto
BartSMP [9]
Sorry I don’t understand your language I wish I could help you but I just don’t understand

3 0
3 years ago
A ball is released from a 10 m high roof and bounces two thirds as high on each successive bounce. After traveling a total of 40
skelet666 [1.2K]

Answer:

Four times traveling 40,12345 mts

Explanation:

We can express this as a sum as follows

\sum_{i=1}^4(10\cdot  \frac{2}{3}^{i - 1} + 10\cdot  \frac{2}{3}^{i } ) = 3250/81=40.12345679

The first term is the dropping part and the second is the upward motion. this sums up to 40,12345 m after bouncing four times. As a program we could write using the while loop.

distance=0;

i:=0;

while distance<40 do

i:=i+1;

distance:=distance+ 10\cdot  \frac{2}{3}^{i - 1} + 10\cdot  \frac{2}{3}^{i };

end while;

Here the answer is in i and the closest distance traveled after reaching 40 is in the variable distance.

4 0
4 years ago
Write a program that simulates a lottery. The program should havean array of five integers named lottery, and shouldgenerate a r
Fiesta28 [93]

Answer:

Here is the C++ program that simulates lottery:

#include<iostream>  //to use input output functions

using namespace std;  //to access objects cin cout

int main(){  //start of main function

int size= 5; // size of arrays

int range = 10;  //range of random numbers from 0 to 9

int user[size];  // user array

int lottery[size];  // lottery array

for(int i=0;i<size;i++)  //iterates through the array

lottery[i]=rand()%range;  // generates random number in specified range

cout<<"Enter "<<size<<" digits: ";  //prompts user to enter 5 digits

for(int i=0;i<size;i++)  //loops through the user array

cin>>user[i];  //reads input digits from user

int match=0;  //stores number of matching digits

for(int i=0;i<size;i++)  //iterates through array to compare user and lottery arrays

if(user[i]==lottery[i])  //if digit at i-th index of user array matches to that of lottery array

match++;  //increments count of matching digits by 1

cout<<"Lottery array: ";  // display digits of lottery array

for(int i=0;i<size;i++)  //iterates through elements of lottery array

cout<<lottery[i]<<" ";  //prints elements of lottery array with a space between them

cout<<endl;  //prints a new line

cout<<"  User  array: ";  // prints digits of user array

for(int i=0;i<size;i++) //iterates through elements of user array

cout<<user[i]<<" ";  //prints elements of user array

cout<<endl;  // prints a new line

if(match==size){  //if all the digits match

cout<<"Congratulations. You are a grand prize winner! "; }//displays this message proclaiming the user as a grand prize winner

else{  // if all digits of user array do not match with lottery array digits

cout<<"Number of digits matched: "<<match<<endl; //displays the number of matched digits

cout<<"Sorry! Better luck next time!" ;    //displays this message when all digits don't match

}

}    

Explanation:

If you want to keep the size and range fixed then you can use #define before the main() function to give a constant value to size and range as:

#define size 5

#define range 10

The program uses rand() function in order to generate random numbers for lottery array in the range of 0 through 9.

Then the program declares a user array with size = 5 and prompts user to enter 5 digits to stores in user array.

Next the program matches each digit of user array to the corresponding digit of lottery array and if the two digits match then the program increments the match variable by 1 to count the matched digits. For example, lets say lottery has the following elements:

lottery: 7,4,9,1,3

Lets say user array has following elements input by user at console

user: 4,2,9,7,3

Now at first iteration the digit 7 at 0-th index of lottery array is matched to the digit 4 at 0-th index of user array. This index is specified using variable i. These means the first element of lottery array is matched with first element of user array. As these digits are not equal so they don't match and the variable i is incremented to point to the position of next digit.

Now at second iteration the digit 4 in lottery array is matched to the digit 2 of user array. As these digits are not equal so they don't match and the variable i is incremented.

at third iteration the digit 9 in lottery array is matched to the digit 9 of user array. As these digits equal so they match and the variable match is incremented to 1 in order to count the number of matches. So value of match = 1

Now at fourth iteration the digit 1 in lottery array is matched to the digit 7 of user array. As these digits are not equal so they don't match and the variable i is incremented. The value of match also remains the same i.e. 1

at fifth iteration the digit 3 in lottery array is matched to the digit 3 of user array. As these digits equal so they match and the variable match is incremented to 1 in order to count the number of matches. So value of match = 2

Next the loop ends because the value of exceeds 5 which is the size of the array.

Next if(match==size) statement has an if condition which checks if all digits match. This is checked by comparing the count of match variable to the size of the array. The value of match is 2 and value of size is 5 so this means that all the digits do not match. Hence this condition evaluates to false. So the statement in if part will not execute and program moves to the statement: cout<<"Number of digits matched: "<<match<<endl; which displays the value of match variable i.e. 2 as:

Number of digits matched: 2

followed by statement cout<<"Sorry! Better luck next time!" ;  which displays the message:

Sorry! Better luck next time!

5 0
3 years ago
Please explain this code line by line and how the values of each variable changes as you go down the code.
Scilla [17]

Answer:

hope this helps. I am also a learner like you. Please cross check my explanation.

Explanation:

#include

#include

using namespace std;

int main()

{

int a[ ] = {0, 0, 0};  //array declared initializing a0=0, a1=0, a3=0

int* p = &a[1]; //pointer p is initialized it will be holding the address of a1 which means when p will be called it will point to whatever is present at the address a1, right now it hold 0.

int* q = &a[0];  //pointer q is initialized it will be holding the address of a0 which means when q will be called it will point to whatever is present at the address a0, right now it hold 0.

q=p; // now q is also pointing towards what p is pointing both holds the same address that is &a[1]

*q=1 ; //&a[0] gets overwritten and now pointer q has integer 1......i am not sure abut this one

p = a; //p is now holding address of complete array a

*p=1; // a gets overwritten and now pointer q has integer 1......i am not sure abut this one  

int*& r = p; //not sure

int** s = &q; s is a double pointer means it has more capacity of storage than single pointer and is now holding address of q

r = *s + 1; //not sure

s= &r; //explained above

**s = 1; //explained above

return 0;

}

6 0
3 years ago
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