Answer:

Explanation:
You can just verify the outputs of the four functions for x = -1, x = 0.25, and x = 1.
1. 

Then, this function does not go through (-1, 0.25)
2. 

Hence, this function goes through the 3 points.
Also, you can verify that it <em>approches y = 0 in quadrant 2</em>, because when x approaches a very large negative number ( - ∞),
becomes very small ( approaches zero). Therefore, this function meets all the requirements: it approaches y = 0 in quadrant 2, <em>increases into quadrant 2, and </em>g<em>oes through </em>the three given points<em>.</em>
Step-by-step explanation:
2x(squared)+9x+9=—1
2x(squared)+9x+9+1=0
2x(squared)+9x+10=0
multiply the coefficient of x and 10=2x10=20
2x(squared)+9x+10=0
look for two numbers that when added gives 9and when multiplied gives 20
2x(squared)+5x+4x+10=0
(2x(squared)+5x)+(4x+10)=0
find the number and letters that are common in the equations
x(2x+5)+2(2x+5)=0
(x+2) (2x+5)=0
x+2=0
collect like terms
x=0-2
x=-2
2x+5=0
collect like terms
2x=0-5
2x=-5
divide both sides by 2
2x/2=-5/2
x=-5/2
so x=-2 and -5/2
You have to divide 288 ÷3 that will give you 96 with no remainder. you can check by multiplying 96×3 that will give you 288 . so you have no remainder. no reams were stored