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Papessa [141]
3 years ago
12

Please help me im confused

Mathematics
2 answers:
slava [35]3 years ago
6 0
Hello, the answer is 0
frosja888 [35]3 years ago
3 0

Answer:

Simplifying

7r + -7r = 0

Combine like terms: 7r + -7r = 0

0 = 0

Solving

0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

Step-by-step explanation:

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It costs $35 per hour to rent a boat at the lake. You also need to pay a $25 fee for safety equipment. You have $200. For how lo
IrinaVladis [17]
$25 + $35x = $200
$35x = $175 (subtracted the 25)
x = 5 hours (divided the 35)

So you could rent the boat for 5 hours.
3 0
3 years ago
A study finds that college students found it unpleasant to sit alone and think.1 The same article describes a second study in wh
Alisiya [41]

Answer:

Assuming a confidence level of 95%.

For the 95% confidence interval the value of \alpha=1-0.95=0.05 and \alpha/2=0.025, with that value we can find the quantile required for the interval in the normal standard distribution.  

z_{\alpha/2}=1.96  

The standard error for this case is given by: SE= 0.154

(0.667-0.25) - 1.96*0.154=0.115  

(0.667-0.25) + 1.96*0.154=0.719  

And the 95% confidence interval for the difference of the two proportions would be given (0.115;0.719).  

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

p_A represent the real population proportion for brand A  

\hat p_A =\frac{12}{18}=0.667 represent the estimated proportion for male

n_A=18 is the sample size required for male

p_B represent the real population proportion for female

\hat p_B =\frac{6}{24}=0.25 represent the estimated proportion for female

n_B=24 is the sample size required for female

z represent the critical value for the margin of error  

The population proportion have the following distribution  

p \sim N(p,\sqrt{\frac{p(1-p)}{n}})  

Solution to the problem

The confidence interval for the difference of two proportions would be given by this formula  

(\hat p_A -\hat p_B) \pm z_{\alpha/2} \sqrt{\frac{\hat p_A(1-\hat p_A)}{n_A} +\frac{\hat p_B (1-\hat p_B)}{n_B}}  

Assuming a confidence level of 95%.

For the 95% confidence interval the value of \alpha=1-0.95=0.05 and \alpha/2=0.025, with that value we can find the quantile required for the interval in the normal standard distribution.  

z_{\alpha/2}=1.96  

The standard error for this case is given by: SE= 0.154

And replacing into the confidence interval formula we got:  

(0.667-0.25) - 1.96*0.154=0.115  

(0.667-0.25) + 1.96*0.154=0.719  

And the 95% confidence interval for the difference of the two proportions would be given (0.115;0.719).  

7 0
3 years ago
Ariana invested $7500 in an account paying in interest rate of 2.9% compounded continuously assuming no deposits or withdrawals
Korvikt [17]

Answer:

11260

Step-by-step explanation:

it is right

7 0
3 years ago
Read 2 more answers
Write an equivalent expression for -5(8-2x)
ololo11 [35]
-40-10x (I think, sry if it’s wrong)
5 0
3 years ago
Haddie wrote a check to the grocery store for $156.00. However, when she looks at her check register later that night, she sees
evablogger [386]
Haddie wrote a check to the grocery store for $156.00. And turns out to only become 122.66 dollars the time she checked it later that night.Now, when she checked it in her banks, I believe there are fees charged to her written check. Now, let's find out how much will that be:=> 156 dollarss to 122.66 dollars=> 33.34 dollars=> 33.34 / 156 =0.21=> 0.21 * 100% = 21%<span>Thus, the bank opted 21% of her written check</span>
5 0
3 years ago
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