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GuDViN [60]
3 years ago
7

The point-slope form of the equation of the line that passes through (–4, –3) and (12, 1) is y – 1 = (x – 12). What is the stand

ard form of the equation for this line?
x – 4y = 8
x – 4y = 2
4x – y = 8
4x – y = 2
Mathematics
2 answers:
a_sh-v [17]3 years ago
8 0
(-4,-3) , (12,1)
slope = (1 - (-3) / (12 - (-4) = 4/16 = 1/4

y - y1 = m(x - x1)
slope(m) = 1/4
(12,1)...x = 12 and y = 1
sub
y - 1 = 1/4(x - 12)
y - 1 = 1/4x - 3
y = 1/4x - 3 + 1
y = 1/4x - 2
-1/4x + y = -2
x - 4y = 8 <=== standard form


aivan3 [116]3 years ago
7 0

Answer:

The answer is x-4y = 8

Other words option A

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