f(x) = 5x²
f(10) = 5(10)² = 5(100) = 500
f'(x) = 10x
f'(10) = 10(10) = 100
Now, find the line that passes through (10, 500) and has a slope of 100
y - y₁ = m(x - x₁)
y - 500 = 100(x - 10)
y - 500 = 100x - 1000
y = 100x - 500
The area of a lateral area of the cylinder is L.S.A. and =

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Answer:a=3/4
b=3/4
Step-by-step explanation:
3a+5b=6
9a+7b=12
-3(3a+5b)=-3(6)
9a+7b=12
-9a-15b=-18
9a+7b=12
-8b=-6
b=3/4
3a+5(3/4)=6
3a+15/4=6
3a=9/4
a=3/4
3(6)+8=26
I think 26 is the answer
Answer:
1
Step-by-step explanation:
this is becasue the slope is positive