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tester [92]
2 years ago
14

What is the absolute value of 3 squared? NO LINKS I NEED THE ANSWER QUICK PLEASE IF YOU CAN

Mathematics
1 answer:
ladessa [460]2 years ago
5 0
The absolute value is 9
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Wendy goes to the gym every 4 days and swims every 6 days. If she went to the gym and swam today, in how many days will she do b
Mice21 [21]

In 12 days, Wendy will do the both again.

Step-by-step explanation:

Given,

Wendy goes to gym every 4 days

Wendy swims every 6 days

We will find the least common multiple of both the numbers in order to determine the number of days in which she will do both.

4 = 4,8,12,16,20,....

6 = 6,12,18,24,.....

Therefore;

The least common multiple of 4 and 6 is 12.

Thus,

In 12 days, Wendy will do the both again.

Keywords: multiples, LCM

Learn more about multiples at:

  • brainly.com/question/10196212
  • brainly.com/question/1021953

#LearnwithBrainly

6 0
3 years ago
9(-4-3)=? Please help
Annette [7]
This is the answer 9(-4-3) = -63
5 0
3 years ago
Read 2 more answers
Using what you know about angles and triangles, what is the measure of angle 6?
zvonat [6]
∠4 = 90  (verticallyopposite)
∠2 = 68 (verticallyopposite)

∠6 = ∠2 + ∠4 (exterior angles = sum of opposite angles)

∠6 = 68 + 90 = 158°

Answer: 158°
7 0
3 years ago
Need po ang answers ASAP nganong po exam namin
Sonja [21]
Opposite of the integers:
+56
+340
-39
-201
-1124

Solid figures:

Cube
Rectangular prism
Cylinder
Octahedron
Triangular pyramid
8 0
3 years ago
What is the equation of the function that is graphed as line a?
valentinak56 [21]
F(x)=-1x-1

1)  Pick 2 points on the line (i chose (-4,3) and (3,-4)
2) Find slope of the line using the 2 points. (work below)
3) Find y-intercept, which is the point where y-axis and the line cross (y-intercept is -1).
4) Place both slope and y-intercept into slope-intercept form, y=mx+b (m=slope and b=y-intercept.)
5) Change y to f(x) (meaning function of x).

Work:
3-(-4)/-4-3=3+4/-4-3=7/-7=-1

y-intercept equals -1 also.

y=mx+b
y=-1x+(-1)
y=-1x-1
f(x)=-1x-1<---Answer

6 0
3 years ago
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