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3 years ago

24 PTS.!!!!!!VERY VERY VERY URGENT PLEASE HELP!!!!!!!! find the least common multiples of 24, 36 and 40 (no listing method!!)

Mathematics

2 answers:

frez [133]3 years ago

7 0

Answer: 360

Step-by-step explanation: don't know how

adelina 88 [10]3 years ago

7 0

Answer: 360

Step-by-step explanation: LCM of 24 , 36 and 40 = 2 × 2 ×2 × 3 × 3 × 5 = 360.

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Question about dilation attached in images.

statuscvo [17]

This is an enlarged dilation

5 0

3 years ago

What is 1/4x24 I need help

ZanzabumX [31]

Answer:

$\boxed{ \bold{ \huge{ \boxed{ \sf{6}}}}}$

Step-by-step explanation:

$\sf{ \frac{1}{4} \times 24}$

Multiply the numerators for the numerator , and multiply the denominators for its denominator and reduce the fraction obtained after Multiplication into lowest term

$\dashrightarrow{ \sf{ \frac{1 \times 24}{4 \times 1}}}$

$\dashrightarrow{ \sf{ \frac{24}{4}}}$

$\dashrightarrow{ \sf{6}}$

Hope I helped!

Best regards! :D

7 0

3 years ago

A roast turkey is taken from an oven when its temperature has reached 185 degrees F and is placed on a table in a room where the

Vedmedyk [2.9K]

(a) Using Newton's Law of Cooling, $\dfrac{dT}{dt} = k(T - T_s)$ , we have $\dfrac{dT}{dt} = k(T - 75)$ where T is temperature after T minutes.
Separate by dividing both sides by T - 75 to get $\dfrac{dT}{T - 75} = k dt$ . Integrate both sides to get $\ln|T - 75| = kt + C$ .

Since $T(0) = 185$ , we solve for C:
$|185 - 75| = k(0) + C\ \Rightarrow\ C = \ln 110$
So we get $\ln|T - 75| = kt + \ln 110$ . Use T(30) = 150 to solve for k:
$\ln| 150 - 75 | = 30k + \ln 110\ \Rightarrow\ \ln 75 - \ln 110= 30k \Rightarrow \\ k= \frac{1}{30}\ln (75/110) = \frac{1}{30}\ln(15/22)$

So

$\ln|T - 75| = kt + \ln 110 \Rightarrow |T - 75| = e^{kt + \ln110} \Rightarrow \\ \\
|T - 75| = 110e^{kt} \Rightarrow T - 75 = \pm110e^{(1/30)\ln(15/22)t} \Rightarrow \\
T = 75 \pm110e^{(1/30)\ln(15/22)t}$

But choose Positive because T > 75. Temp of turkey can't go under.

$T(t) = 75 + 110e^{(1/30)\ln(15/22)t} \\
T(45) = 75 + 110e^{(1/30)\ln(15/22)(45)} = 136.929 \approx 137{}^{\circ}F$

(b)

$T(t) = 75 + 110e^{(1/30)\ln(15/22)t} = 75 + 110(15/22)^{t/30} \\
100 = 75 + 110(15/22)^{t/30} \\
25 = 110(15/22)^{t/30} 
\frac{25}{110} = (15/22)^{t/30} \\
\ln(25/110) / ln(15/22) = t/30 \\
t = 30\ln(25/110) / ln(15/22) \approx 116\ \mathrm{min}$

Dogs of the AMS.

4 0

3 years ago

Find the equation of the line.

Grace [21]

Answer:

m: $-\frac{1}{3}$

Step-by-step explanation:

Pick two points (0,5) and (3,4)

use the formula to find slope: $\frac{y2-y1}{x2-x1}$

Insert values: $\frac{4-5}{3-0}$

m: $-\frac{1}{3}$

:-)

7 0

3 years ago

Someone help me please!!

Alex_Xolod [135]

Step-by-step explanation:

<em>it is a right angle triangle</em>

30square =14square +x square

900=196+xsquare

900-196=xsquare

704=xsquare

root704=x

26.532=x

90+26.532=63.468

180-63.468=116.532degree

8 0

3 years ago