<h3>Given</h3>
- an exponential curve with points (-3, 12) and (-2, 7)
- a horizontal asymptote of y=2
<h3>Find</h3>
- the equation of the curve
<h3>Solution</h3>
Since the horizontal asymptote of a plain exponential curve is y=0, your curve has been shifted up 2 units. So, we know the function is something of the form ...
... y = 2 + a·b^x
Putting in the given point values, we have
... 12 = 2 + a·b^(-3)
... 7 = 2 + a·b^(-2)
Subtracting 2 from each of these equations and finding their ratio gives
... (12-2)/(7-2) = (2+a·b^(-3) -2)/(2+a·b^(-2) -2)
... 10/5 = b^-1 . . . . . simplify
... b = 2^(-1) = 1/2
Then we can use either of the given data points to find <em>a</em>.
... 12 = 2 + a·(1/2)^(-3)
... 10 = 8a
... 10/8 = a = 1.25
So, the equation for the curve is ...
... y = 2 + 1.25·0.5^x
Answer:
13) x=3.5
14) x=6
Step-by-step explanation:
There are 60 different ways to schedule your classes
24.50 would be the answer for the question you are asking.
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