m∠BAC = 27°
Solution:
ABCD is a quadrilateral.
AB and CD are parallel lines.
Given m∠BCD = 54°
AC bisect ∠BCD.
m∠DCA + m∠CAB = m∠BCD
m∠DCA + m∠DCA = 54° (since ∠ACB = ∠DCA)
2 m∠DCA = 54°
Divide by 2 on both sides, we get
m∠DCA = 27°
AB and CD are parallel lines and AC is the transversal.
<em>If two parallel lines cut by a transversal, then the alternate interior angles are equal.</em>
m∠BAC = m∠DCA
m∠BAC = 27°
Hence m∠BAC = 27°.
360, 356, 364.71547154... , 359.99, and 360.1.
Answer:
9,338 is the product of the equation
D= -10
explanation:
-90/9=-10
Answer:
So the answer is (3, 0) on a graph.
Step-by-step explanation:
What I use is a graphing calculator. It helps tremendously. It is called desmos.com. Hope this helps.
