<span>A(x, y) → (x - 3, y + 1)</span>
I believe it’s -8 as if you add nothing to -8 which in this case is zero the integer would stay the same.
7c² + 8c + 1 = 0
c = <u>-(8) +/- √((8)² - 4(7)(1))</u>
2(7)
c = <u>-8 +/- √(64 - 28)</u>
14
c = <u>-8 +/- √(36)
</u> 14
c = <u>-8 +/- 6</u>
14
c = <u>-8 + 6</u> c = <u>-8 - 6</u>
14 14
c = <u>2</u> c = <u>-14</u>
14 14
c = ¹/₇ c = 1
The solution is equal to { 1, ¹/₇}.
<u />
Answer:
-4 and 4
Step-by-step explanation: