You use a system of equations to solve this.
x will be one integer and y will be the other.

2y - 7 = x
x^2 + y^2 = 433

You can plug (2y - 7) in for x in the second equation.

(2y - 7)^2 + y^2 = 433
4y^2 - 28y + 49 + y^2 = 433
5y^2 - 28y -384 = 0
y = 12 or -32/5

It has to be 12 since -32/5 is not an integer.

Plug 12 in for y to get x.

2(12) - 7 = x
x = 17

The integers are 12 and 17.

6 0

4 years ago

A teacher gives a test to a large group of students. The results are closely approximated by a normal curve. Teh mean is 73, wit

zavuch27 [327]

Answer:

The bottom for an A is 75. Round to the nearest whole number as needed.

Step-by-step explanation:

1) Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Let X the random variable that represent the scores on this case, and for this case we know the distribution for X is given by:

$X \sim N(\mu=73,\sigma=7)$

And let $\bar X$ represent the sample mean, the distribution for the sample mean is given by:

$\bar X \sim N(\mu,\frac{\sigma}{\sqrt{n}})$

2) The bottom for an A is _____. Round to the nearest whole number as needed.

And we want the top 5.5% of the scores, so we need a value a such that:

$P(X>a)=0.055$ or $P(X$

We need on the right tail of the distribution a value a that gives to us 94.5% of the area below and 5.5% of the area above. Both conditions are equivalent.

Let's use the condition $P(X$ , the best way to solve this problem is using the z score with the following formula:

$z=\frac{x-\mu}{\sigma}$

So we need a value from the normal standard distribution that accumulates 0.945 of the area on the left and 0.055 on the right. This value on this case is 1.598 and we can founded with the following code in excel:

"=NORM.INV(0.945,0,1)"

If we apply the z score formula to our case we have this:

$P(X$

So then based on the equalities we have this:

$\frac{a-73}{7}=1.598$

And if we solve for a we got:

$a=(7*1.598) +73=84.186$

So then we need a score of 84.186 rounded to the nearest whole number 75 or higher in order to get an A

8 0

3 years ago

Two bags had 100 kilograms of sugar each. after taking out 3 times as much sugar from bag one than bag two, bag one had half as

Serjik [45]

According to the given statement, we can get the equation:

50 - 3x = 1/2 (50-x)

where x = amount removed from bag two, 3x removed from bag one

Then we multiply both sides by 2 (to eliminate the ½)

100-6x= 50-x

Add 6x to both sides

100= 50-5x

Then subtract 50 from both sides

50=5x

Lastly, divide by 5

10=x

Therefore 10 kg of sugar was removed from bag 2

further, 3x= 30, so 30 kg of sugar was removed from bag 1.

50-30=20 kg remaining in bag 1.

<span>50-10=40 kg remaining in bag 2.</span>

6 0

4 years ago

Read 2 more answers

Some plz solve both for meeeeee <33

Mademuasel [1]

10. 4w^2 + 7w^2 + 7z^2

Combine each term with the same variable.

11w^2 + 7z^2

This is in simplest form.

11. 3x + 4(5x + 2)

Multiply each term inside the parentheses by 4.

3x + 20x + 8

Combine all the terms with the same variable.

23x + 8

This is in simplest form.

6 0

4 years ago