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3 years ago

Helppppppppppppppppp

Mathematics

1 answer:

earnstyle [38]3 years ago

8 0

Answer:

17/24

Step-by-step explanation:

-5/8 -(-4/3)

-5/8+4/3

-15/24+32/24

17/24 would be your answer

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Leto [7]

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3mg per BID vistrail

Step-by-step explanation:

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3 years ago

Suppose \nabla f (x,y) = 3 y \sin(xy) \vec{i} + 3 x \sin(xy)\vec{j}, \vec{f} = \nabla f(x,y), and c is the segment of the parabo

Anna11 [10]

I'll assume you're supposed to compute the line integral of $\nabla f$ over the given path $C$ . By the fundamental theorem of calculus,

$\displaystyle\int_C\nabla f(x,y)\cdot\mathrm d\vec r=f(4,48)-f(1,3)$

so evaluating the integral is as simple as evaluting $f$ at the endpoints of $C$ . But first we need to determine $f$ given its gradient.

We have

$\dfrac{\partial f}{\partial x}=3y\sin(xy)\implies f(x,y)=-3\cos(xy)+g(y)$

Differentiating with respect to $y$ gives

$\dfrac{\partial f}{\partial y}=3x\sin(xy)=3x\sin(xy)+\dfrac{\mathrm dg}{\mathrm dy}\implies\dfrac{\mathrm dg}{\mathrm dy}=0\implies g(y)=C$

and we end up with

$f(x,y)=-3\cos(xy)+C$

for some constant $C$ . Then the value of the line integral is $-3\cos192+3\cos3$ .

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4 years ago

What’s the area of these 3?

arlik [135]

Answer:

7.484 8.38.4 9.380.3

Step-by-step explanation:

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3 years ago

Can someone please help me!!!

CaHeK987 [17]

Answer:

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Step-by-step explanation:

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3 years ago

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Andrei [34K]

Answer:

50 dollars

Step-by-step explanation: 99.99 plus 23.51 = 123.5. 123.5 minus 73.50 = 50

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3 years ago

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Helppppppppppppppppp