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3 years ago

Hi w do you find c for standard normal distribution

Mathematics

1 answer:

siniylev [52]3 years ago

5 0

You need to a table of the standard normal cumulative distribution
Here is one:
https://math.ucalgary.ca/files/math/normal_cdf.pdf

the closest value I see is 0.85

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Math be like 0-0????

pashok25 [27]

Answer: A & C

Step-by-step explanation:

HL is Hypotenuse-Leg

A) the hypotenuse from ΔABC ≡ the hypotenuse from ΔFGH

a leg from ΔABC ≡ a leg from ΔFGH

Therefore HL Congruency Theorem can be used to prove ΔABC ≡ ΔFGH

B) a leg from ΔABC ≡ a leg from ΔFGH

the other leg from ΔABC ≡ the other leg from ΔFGH

Therefore LL (not HL) Congruency Theorem can be used.

C) the hypotenuse from ΔABC ≡ the hypotenuse from ΔFGH

at least one leg from ΔABC ≡ at least one leg from ΔFGH

Therefore HL Congruency Theorem can be used to prove ΔABC ≡ ΔFGH

D) an angle from ΔABC ≡ an angle from ΔFGH

the other angle from ΔABC ≡ the other angle from ΔFGH

AA cannot be used for congruence.

5 0

3 years ago

the blue lake trail is 11 3/8 miles long. gemma has hiked 2 1/2 miles each hour for 3 hours. how far is she from the end?

lisov135 [29]

2 4/8 x 3 = 7 4/8
11 3/8 - 7 4/8 = 3 7/8 miles from the end

8 0

4 years ago

Write the inverse function, f^-1 (x), for the function f (x) = 2x + 3

cricket20 [7]

$f(x) = 2x + 3$

$y = 2x + 3$

Subtract the sides of the equation minus 3

$y - 3 = 2x$

Divided the sides of the equation by 2

$\frac{y - 3}{2} = x \\$

So ;

${f}^{ - 1}(x) = \frac{x - 3}{2} \\$

_________________________________

And we're done.

Thanks for watching buddy good luck.

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6 0

3 years ago

A rectangle has area 64 m2. Express the perimeter of the rectangle as a function of the length L of one of its sides. State the

svp [43]

A rectangle is a two-dimensional shape with two sets of equal, parallel sides. These dimensions are the length (L) and the width (W). The formula for the rectangle's area is the product of the two dimensions. The formula for perimeter is

P = 2L + 2W

Since
A = LW = 64
W = 64/L
Substituting to the formula for perimeter would be,

P = 2L + 2(64/L)
P = 2L + 128/L

3 0

3 years ago

Multiply or divide as indicated. p^8 • p^-3 • p^2

NeTakaya

P^8 • p^−3 • p^2=p^10/p^3=p7

3 0

3 years ago