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Rudiy27
3 years ago
7

Explain two ways by which the calendar meets or fails to meet the criteria of showing the correct data

Computers and Technology
1 answer:
gtnhenbr [62]3 years ago
7 0

Answer:

The two ways the calendar meets the criteria of showing the correct date are;

1) The calendar can give dates in the 12 months in a year

2) The calendar can show up to the 31 different days in a month

Explanation:

The two ways in which the calendar meets the criteria of showing the correct date are;

1) The number number of long blocks with 4 different months each = Three

Therefore, the total number of months the blocks can hold = 3 × 4 months = 12 months = The number of months in a year

2) The number of faces on each dice = 6 faces

The number of dice = 2 dice

The total number of faces = 12

The number of identical faces = 2 (11th and 22nd of the month)

The number of unique faces = 10

The number of combinations of the dices = ₁₀C₂ = 45

The number of combination of faces required to show = 1 to 31 = 31 combination

Therefore, there are adequate combinations on the dice to show all the dates of month

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Answer:

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What is word processing?
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A. Citing sources for documents you found on the web
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Write a Python function check_subset() that takes in two Python lists, representing sets of integers, A and B. Your function sho
wlad13 [49]

Answer:

  1. def check_subset(l1, l2):
  2.    status = False
  3.    count = 0
  4.    if(len(l1) > len(l2)):
  5.        for x in l2:
  6.            for y in l1:
  7.                if x == y:
  8.                    count += 1
  9.        if(count == len(l2)):
  10.            return True  
  11.        else:
  12.            return False
  13.    else:
  14.        for x in l1:
  15.            for y in l2:
  16.                if x==y:
  17.                    count += 1
  18.        if(count == len(l1)):
  19.            return True  
  20.        else:
  21.            return False
  22. print(check_subset([1,4,6], [1,2,3,4,5,6]))
  23. print(check_subset([2,5,7,9,8], [7,8]))
  24. print(check_subset([1, 5, 7], [1,4,6,78,12]))

Explanation:

The key idea of this solution is to create a count variable to track the number of the elements in a shorter list whose value can be found in another longer list.

Firstly, we need to check which list is shorter (Line 4). If the list 2 is shorter, we need to traverse through the list 2 in an outer loop (Line 5) and then create another inner loop to traverse through the longer list 1 (Line 6).  If the current x value from list 2 is matched any value in list 1, increment the count variable by 1. After finishing the outer loop and inner loop, we shall be able to get the total count of elements in list 2 which can also be found in list 1. If the count is equal to the length of list 2, it means all elements in the list 2 are found in the list 1 and therefore it is a subset of list 1 and return true (Line 10-11) otherwise return false.

The similar process is applied to the situation where the list 1 is shorter than list 2 (Line 15-24)

If we test our function using three pairs of input lists (Line 26-28), we shall get the output as follows:

True

True

False

6 0
3 years ago
Write a program that allows a user to choose to roll between 1 and 100 dice between 1 and 1000 times
s344n2d4d5 [400]

Answer:

Here is a Python program that allows a user to choose to roll between 1 and 100 dice between 1 and 1000 times. The program uses a while loop to continuously prompt the user for input until they enter a valid number of dice and rolls. It also uses a for loop to simulate the dice rolls and a random module to generate random numbers for the dice rolls.

import random

while True:

   # Prompt the user for the number of dice to roll

   num_dice = int(input("Enter the number of dice to roll (1-100): "))

   if num_dice < 1 or num_dice > 100:

       continue

   # Prompt the user for the number of rolls to perform

   num_rolls = int(input("Enter the number of rolls to perform (1-1000): "))

   if num_rolls < 1 or num_rolls > 1000:

       continue

   # Simulate the dice rolls and print the results

   for i in range(num_rolls):

       roll = 0

       for j in range(num_dice):

           roll += random.randint(1, 6)

       print(f"Roll {i+1}: {roll}")

   # Ask the user if they want to roll again

   again = input("Roll again? (Y/N): ").upper()

   if again != "Y":

       break

Explanation:

In this program, we first import the random module to use its randint function to generate random numbers for the dice rolls. We then enter a while loop that will continuously prompt the user for input until they enter a valid number of dice and rolls. Within the while loop, we prompt the user for the number of dice to roll and the number of rolls to perform. If the user enters an invalid number of dice or rolls, we continue back to the beginning of the loop and prompt the user again.

Once the user has entered a valid number of dice and rolls, we use a for loop to simulate the dice rolls. For each roll, we use another for loop to roll the specified number of dice and add up the results. We then print the total for each roll. After all of the rolls have been performed, we ask the user if they want to roll again. If they enter "Y", we continue back to the beginning of the while loop to prompt them for new input. If they enter anything else, we break out of the while loop and end the program.

Overall, this program allows a user to choose to roll between 1 and 100 dice between 1 and 1000 times, and simulates the dice rolls using random numbers and loops.

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Answer:

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8 0
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