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3 years ago

Explain two ways by which the calendar meets or fails to meet the criteria of showing the correct data

Computers and Technology

1 answer:

gtnhenbr [62]3 years ago

7 0

Answer:

The two ways the calendar meets the criteria of showing the correct date are;

1) The calendar can give dates in the 12 months in a year

2) The calendar can show up to the 31 different days in a month

Explanation:

The two ways in which the calendar meets the criteria of showing the correct date are;

1) The number number of long blocks with 4 different months each = Three

Therefore, the total number of months the blocks can hold = 3 × 4 months = 12 months = The number of months in a year

2) The number of faces on each dice = 6 faces

The number of dice = 2 dice

The total number of faces = 12

The number of identical faces = 2 (11th and 22nd of the month)

The number of unique faces = 10

The number of combinations of the dices = ₁₀C₂ = 45

The number of combination of faces required to show = 1 to 31 = 31 combination

Therefore, there are adequate combinations on the dice to show all the dates of month

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matrenka [14]

Answer:

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Explanation:

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3 years ago

write a C program the prints out the size of variables with the following C data types- int, long, unsigned, long long, double,

Anit [1.1K]

C program for finding size of different data types

#include <stdio.h>

//driver function

int main()

{

int a; //declaring a of type int

float b; //declaring b of type float

double c; //declaring c of type double

char d; //declaring d of type char

long e; //declaring e of type long

long long f; //declaring f of type longlong

unsigned g; //declaring g of type unsigned

// Sizeof operator is used to evaluate the size of a variable

printf(" int data type contains: %lu bytes\n",sizeof(a));/*Finding size of int */

printf("float data type contains : %lu bytes\n",sizeof(b));/*Finding size of float */

printf("double data type contains: %lu bytes\n",sizeof(c));/*Finding size of double */

printf("char data type contains: %lu byte\n",sizeof(d));/*Finding size of char */

printf("long data type contains: %lu byte\n",sizeof(e));/*Finding size of long*/ printf("longlong data type contains: %lu byte\n",sizeof(f));/*Finding size of longlong */

printf("unsigned data type contains: %lu byte\n",sizeof(g)); /*Finding size of unsigned */

return 0;

}

Output

int data type contains: 4 bytes

float data type contains : 4 bytes

double data type contains: 8 bytes

char data type contains: 1 byte

long data type contains: 8 byte

longlong data type contains: 8 byte

unsigned data type contains: 4 byte

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3 years ago

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They are concerned about many things

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3 years ago

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Lady bird [3.3K]

Answer:

fire

Explanation:

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3 years ago

Using recursion, write a program that asks a user to enter the starting coordinates (row, then column), the ending coordinates (

Luden [163]

Answer:

The program in Python is as follows

def Paths(row,col):

if row ==0 or col==0:

return 1

return (Paths(row-1, col) + Paths(row, col-1))

row = int(input("Row: "))

col = int(input("Column: "))

print("Paths: ", Paths(row,col))

Explanation:

This defines the function

def Paths(row,col):

If row or column is 0, the function returns 1

if row ==0 or col==0:

return 1

This calls the function recursively, as long as row and col are greater than 1

return (Paths(row-1, col) + Paths(row, col-1))

The main begins here

This prompts the user for rows

row = int(input("Row: "))

This prompts the user for columns

col = int(input("Column: "))

This calls the Paths function and prints the number of paths

print("Paths: ", Paths(row,col))

4 0

3 years ago