Problem
The perimeter of a rectangle is less than 10 inches. The length is x and the width is x - 5. If the solution is x<5, ThEn the length is less than 5. Is this viable solution.
Solution
For this case the perimete rof a rectangle is given by:
P= 2x+2y
x= lenght y = width
And we also know that y= x-5
And replacing the condition given: P<10 we got:
2x +2y <10
2x +2(x-5)<10
4x -10 >10
And we can rewrite as:
4x >20
x>5
So then the best answer would be:
B. non viable
<h3>The answer is A.</h3>
You must factor the numerator and denominator and cancel the common factors.
9514 1404 393
Answer:
D. (-3, -2)
Step-by-step explanation:
The equations have different coefficients for x and y, so will have one solution. The solutions offered are easily tested in either equation.
Using (x, y) = (-2, -3):
x = y -1 ⇒ -2 = -3 -1 . . . . False
Using (x, y) = (-3, -2):
x = y -1 ⇒ -3 = -2 -1 . . . .True
2x = 3y ⇒ 2(-3) = 3(-2) . . . . True
The solution is (-3, -2).
__
If you'd like to solve the set of equations, substitution for x works nicely.
2(y -1) = 3y
2y -2 = 3y . . eliminate parentheses
-2 = y . . . . . . subtract 2y
x = -2 -1 = -3
The solution is (x, y) = (-3, -2).
Step-by-step explanation:
Compounded quarterly means n=4
Answer:
82.5 sq in
Step-by-step explanation:
15 × 11 = 165
165/2 = 82.5
82.5 sq in