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2 years ago

The endpoints of a diameter of a circle are (3, -2) and (-5, 8). What is the equation of the circle in standard form?

Mathematics

1 answer:

RUDIKE [14]2 years ago

4 0

Answer:

(x + 1)² + (y − 3)² = 41

Step-by-step explanation:

The center of the circle is the midpoint of the diameter.

(h, k) = ((x₂ + x₁)/2, (y₂ + y₁)/2)

(h, k) = ((3 + -5)/2, (-2 + 8)/2)

(h, k) = (-1, 3)

The radius is half the length of the diameter.

r = ½ √((x₂ − x₁)² + (y₂ − y₁)²)

r = ½ √((3 − -5)² + (-2 − 8)²)

r = ½ √(8² + 10²)

r = √41

Therefore, the equation of the circle is:

(x − h)² + (y − k)² = r²

(x + 1)² + (y − 3)² = 41

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