<span>B. 16 quarts of the 2% milk and 24 quarts of the 7% milk
First, let's create an equation to solve.
x = quarts of 2% milk
(40-x) = quarts of 7% milk
So we have the equation
x*2 + (40-x)*7 = 40*5
Now to solve for x
x*2 + (40-x)*7 = 40*5
x*2 + 7*40 - 7*x = 40*5
x*2 - 7*x = 40*5 - 7*40
-5*x = - 2*40
x = 2*8
x = 16
So we need 16 quarts of 2% milk and 40-16 = 24 quarts of 7%, which matches option "B".</span>
Answer:
2+n/5
Step-by-step explanation:
sum=plus
quotient=divide
number=n
Answer:
x = -36, y = 6, z = -6
Step-by-step explanation:
The requirement x/z = -z means x = -z².
The requirement x/y = z means x = yz.
These two requirements together mean yz = -z², or y = -z.
The requirements that z/2 and z/3 are integers mean that z is a multiple of 2·3 = 6. The smallest magnitude non-zero multiple is z=-6 (since we also require z < -z).
Using z=-6, we have x = -z² = -36; y = -(-6) = 6.
For some positive integer n, ...
... x = -36n², y = 6n, z = -6n.
-7-w<10
Add 7 to each side
-w<17
Change signs and flip sign
w>17
Hope this helps :)
