Answer:
i think it would be 400=10d
So it tells us that g(3) = -5 and g'(x) = x^2 + 7.
So g(3) = -5 is the point (3, -5)
Using linear approximation
g(2.99) is the point (2.99, g(3) + g'(3)*(2.99-3))
now we just need to simplify that
(2.99, -5 + (16)*(-.01)) which is (2.99, -5 + -.16) which is (2.99, -5.16)
So g(2.99) = -5.16
Doing the same thing for the other g(3.01)
(3.01, g(3) + g'(3)*(3.01-3))
(3.01, -5 + 16*.01) which is (3.01, -4.84)
So g(3.01) = -4.84
So we have our linear approximation for the two.
If you wanted to, you could check your answer by finding g(x). Since you know g'(x), take the antiderivative and we will get
g(x) = 1/3x^3 + 7x + C
Since we know g(3) = -5, we can use that to solve for C
1/3(3)^3 + 7(3) + C = -5 and we find that C = -35
so that means g(x) = (x^3)/3 + 7x - 35
So just to check our linear approximations use that to find g(2.99) and g(3.01)
g(2.99) = -5.1597
g(3.01) = -4.8397
So as you can see, using the linear approximation we got our answers as
g(2.99) = -5.16
g(3.01) = -4.84
which are both really close to the actual answer. Not a bad method if you ever need to use it.
Answer:
Step-by-step explanation:
If you want to find the equation of line with a given a slope of which goes through the point (-4,5), you can simply use the point-slope formula to find the equation:
---Point-Slope Formula---
where is the slope, and is the given point
So lets use the Point-Slope Formula to find the equation of the line
Plug in , , and (these values are given)
Distribute
Multiply and to get
Add -1 to both sides to isolate y
Combine like terms and to get the answer
So the equation of the line with a slope of which goes through the point (-4,5) is:
which is now in y=mx = b form where the slope is m=-4/5 and the y-intercept is b=1
Answer: a is 2.2, b is 0.55
Explanation:
To find the x intercept, put 0 instead of y,
hence,
0=-0.25x+0.55
-0.25x=-0.55
x=2.2
To find y intercept put 0 instead of x,
so,
y=-0.25*0+0.55
y=0+0.55
y=0.55
