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alexdok [17]
3 years ago
10

Gerald is conducting an experiment with 3 possible outcomes. Kasey is conducting an experiment with 20 possible

Mathematics
1 answer:
Pepsi [2]3 years ago
3 0

Answer:

Gerald will need to conduct fewer trials because experimental and theoretical results in experiments with small

numbers of possible outcomes are the same.

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Number 2 I need help on how to solve it
Hunter-Best [27]

Let's simplify the following expression:

\text{ }\frac{\text{ \lparen2x}^4\text{ - y}^6\text{z}^{-4})^2}{\text{ 2x}^2\text{z}^3}\text{ }\cdot\text{ }\frac{\text{ 6x}^5\text{y}^{-4}\text{z}^{-5}}{\text{ \lparen2x}^6\text{y}^3\text{z}^{-3})^2}

We get,

\text{ }\frac{(\text{2x}^4\text{ - y}^6\text{z}^{-4})^2}{\text{ 2x}^2\text{z}^3}\text{ }\cdot\text{  }\frac{6x^5y^{-4}z^{-5}}{(2x^6y^3z^{-3})^2}\text{ }\frac{(2x^4-y^6z^{-4})^2(6x^5y^{-4}z^{-5})}{(2x^2z^3)(2x^6y^3z^{-3})^2}\text{ }\frac{(4x^8\text{ - 4x}^4y^6z^{-4}\text{ + y}^{12}z^{-8})(6x^5y^{-4}z^{-5})}{(2x^2z^3)(4x^{12}y^6z^{-6})}\text{ }\frac{24x^{13}y^{-4}z^{-5}\text{ - 24x}^9y^2z^{-9}\text{ + 6x}^5y^8z^{-13}}{8x^{14}y^6z^{-3}}

4 0
1 year ago
write an expression that represents the cost of one carful of nonstudents ($12 per person). Use x as the number of people who ri
gayaneshka [121]
Okay so each person is $12


Then you need to times that for how many people are in the car x.


Since x is a variable and not a number it can go right next to the 12


You answer should be 12x
7 0
3 years ago
What is the slope of a line that is parallel to the line y=3/4x+2
stepladder [879]
If two lines are parallel to one another, then their slopes are identical.  The slope in the line above is 3/4.  Therefore, a line parallel to that line will also have a slope of 3/4, it will just have a different y-intercept.
4 0
3 years ago
Lucio quiere repartir su colección de estampillas entre la mayor cantidad de amigos pero de manera que todos reciban la misma ca
Daniel [21]

Answer:

Lucio podrá armar 5 grupos iguales de estampillas.

Step-by-step explanation:

El problema plantea un caso de distribución mediante la aplicación del divisor común mayor a todos los números involucrados. Para ello, primero debemos analizar los divisores de cada uno de estos números:

-30: divisible por 2, 3, 5, 6, 10, 15 y 30.

-75: divisible por 3, 5, 15, 25 y 75.

-160: divisible por 2, 4, 5, 8, 10, 16, 20, 32, 40, 80 y 160.

Así, podemos ver que el divisor común mayor a los tres números es 5, ya que 30, 75 y 160 dan como resultado un número entero tras ser divididos por 5.

Entonces, para poder repartir equitativamente sus estampillas entre la mayor cantidad de amigos posibles, deberá repartir 6 estampillas de animales, 15 estampillas de flores y 32 estampillas de ciudades a 5 amigos. De esta manera, Lucio podrá armar 5 grupos iguales de estampillas.

4 0
3 years ago
2. What are the next three terms in the geometric sequence below?
Elza [17]
-0.5 and 2 the difference is 2.5. 2.5 times 4 equals 10. 2 and -8 the difference is 10. 10 times 4 equals 40. -8 and 32 the difference is 40
7 0
3 years ago
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