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alexdok [17]
3 years ago
10

Gerald is conducting an experiment with 3 possible outcomes. Kasey is conducting an experiment with 20 possible

Mathematics
1 answer:
Pepsi [2]3 years ago
3 0

Answer:

Gerald will need to conduct fewer trials because experimental and theoretical results in experiments with small

numbers of possible outcomes are the same.

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Help me with 24 “ find the value of x”
Tatiana [17]

Answer:

x = 5°

Step-by-step explanation:

2x+20 = 3x +15 —> Opposite angles

3x - 2x = 20 - 15

x = 5

I hope I helped you^_^

6 0
3 years ago
Read 2 more answers
K(x)= -3x - 3; find k(-2)
Anastaziya [24]

Answer:

\huge{k( - 2)} = 3

Step-by-step explanation:

K(x)= -3x - 3

To find the value of k substitute the value of k that's -2 into the original expression and solve for the value of k.

That's

k( - 2) =  - 3( - 2) - 3 \\  = 6 - 3 = 3

We have the final answer as

<h3>k(-2) = 3</h3>

Hope this helps you

6 0
3 years ago
How is this solved using trig identities (sum/difference)?
GenaCL600 [577]
FIRST PART
We need to find sin α, cos α, and cos β, tan β
α and β is located on third quadrant, sin α, cos α, and sin β, cos β are negative

Determine ratio of ∠α
Use the help of right triangle figure to find the ratio
tan α = 5/12
side in front of the angle/ side adjacent to the angle = 5/12
Draw the figure, see image attached

Using pythagorean theorem, we find the length of the hypotenuse is 13
sin α = side in front of the angle / hypotenuse
sin α = -12/13

cos α = side adjacent to the angle / hypotenuse
cos α = -5/13

Determine ratio of ∠β
sin β = -1/2
sin β = sin 210° (third quadrant)
β = 210°

cos \beta = -\frac{1}{2}  \sqrt{3}

tan \beta= \frac{1}{3}  \sqrt{3}

SECOND PART
Solve the questions
Find sin (α + β)
sin (α + β) = sin α cos β + cos α sin β
sin( \alpha + \beta )=(- \frac{12}{13} )( -\frac{1}{2}  \sqrt{3})+( -\frac{5}{13} )( -\frac{1}{2} )
sin( \alpha + \beta )=(\frac{12}{26}\sqrt{3})+( \frac{5}{26} )
sin( \alpha + \beta )=(\frac{5+12\sqrt{3}}{26})

Find cos (α - β)
cos (α - β) = cos α cos β + sin α sin β
cos( \alpha + \beta )=(- \frac{5}{13} )( -\frac{1}{2} \sqrt{3})+( -\frac{12}{13} )( -\frac{1}{2} )
cos( \alpha + \beta )=(\frac{5}{26} \sqrt{3})+( \frac{12}{26} )
cos( \alpha + \beta )=(\frac{5\sqrt{3}+12}{26} )

Find tan (α - β)
tan( \alpha - \beta )= \frac{ tan \alpha-tan \beta }{1+tan \alpha  tan \beta }
tan( \alpha - \beta )= \frac{ \frac{5}{12} - \frac{1}{2} \sqrt{3}   }{1+(\frac{5}{12}) ( \frac{1}{2} \sqrt{3})}

Simplify the denominator
tan( \alpha - \beta )= \frac{ \frac{5}{12} - \frac{1}{2} \sqrt{3}   }{1+(\frac{5\sqrt{3}}{24})}
tan( \alpha - \beta )= \frac{ \frac{5}{12} - \frac{1}{2} \sqrt{3} }{ \frac{24+5\sqrt{3}}{24} }

Simplify the numerator
tan( \alpha - \beta )= \frac{ \frac{5}{12} - \frac{6}{12} \sqrt{3} }{ \frac{24+5\sqrt{3}}{24} }
tan( \alpha - \beta )= \frac{ \frac{5-6\sqrt{3}}{12} }{ \frac{24+5\sqrt{3}}{24} }

Simplify the fraction
tan( \alpha - \beta )= (\frac{5-6\sqrt{3}}{12} })({ \frac{24}{24+5\sqrt{3}})
tan( \alpha - \beta )= \frac{10-12\sqrt{3} }{ 24+5\sqrt{3}}

7 0
3 years ago
Answers:
Anit [1.1K]
Can I see the picture it’s blurry
4 0
3 years ago
Read 2 more answers
Jack’s bill at a restaurant came to $52.31. He wants to leave a 15% tip. How much will the new total be, including tip?
blondinia [14]
52.31*1.15=60.1565

round it to the nearest penny and you will get $60.16
4 0
4 years ago
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