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3 years ago

PLS HELP ME!!! 10 points for the answer and an explanation.

Mathematics

1 answer:

noname [10]3 years ago

7 0

Answer:

On Monday the chef made 1 and 1/3 of a batch

On Sunday the chef made 2 and 4.5/9 of a batch

I think this is the answer, hope it helps!

You might be interested in

Which expressions show the expanded form for 200.06 choose all answers that are correct.

Anit [1.1K]

a. 2 x 100 0 x 1 0 x 1/10 6 1/100b. 2 x 100 0 x 1 0 x 1/100 6 1/1000

Hope it helps! :D

Btw, where is B?

4 0

3 years ago

Find the average rate of change for f(x) = x2 + 9x + 18 from x = −10 to x = 10.

igor_vitrenko [27]

The average rate of change formula is
f(b) - f(a)
arc = ----------------
b-a

Here, a= -10 and b = 10

(10)^2 + 9(10) + 18 - [ (-10)^2 + 9(-10) + 18]
Here arc = --------------------------------------------------------------
10 - (-10)

10^2 and -(-10)^2 cancel. 18 - 18 cancel.

90 - (-90) 180
This leaves us with arc = ----------------- = ------------- = 9 (answer)
20 20

7 0

3 years ago

(d) Given that n(§) = 96, n(A) = 50 and n(B) = 60. Find the maximum and minimum values for n(An B).

frez [133]

Step-by-step explanation:

the max. value is when the smaller set (A) is completely contained in the larger set (B).

then n(A n B) is n(A) = 50.

the set intersection between A and B cannot get bigger than that. or A gets bigger ...

after all, the intersection means it is a set of all elements that exist in BOTH sets.

but then there must be other elements besides A and B in the universal set too, because n(universal set) = 96, and n(A u B) would be only 60.

the min. value could be the empty set or 0. but because n(universal set) = 96, and n(A) + n(B) = 110 and larger than 96, it means that there have to be some shared elements. at least 110 - 96 = 14 elements.

in this case there cannot be other elements in the universal set than A and B. and n(universal set) = n(AuB) = 96.

3 0

1 year ago

Rachel has 60 scones. She sells them to Robbie, Cameron, Louis, Tom and

Nutka1998 [239]

We can start by writing all that we know about the problem. Let us write down how many scones each boy has:
$R_{o} : x$
$C_{a} : x+k$
$L_{o} : x+2k$
$T_{o} : x+3k$
$C_{h} : x+4k$
Note that k is the increase, we know it's a constant. This is not a system of equations, please keep that in mind. We will use rest of the information given to build the system. We have two variables x (the number of cookies the first boy bought) and k( the increase), that means we need to have two equations to solve this problem.
We know that total amount of scones is 60, so we can use that information to build our first equation. We sum all of the scones and we get 60.
$R_{o}+C_{a}+L_{o}+T_{o}+C_{h}=60$
$5x+10k=60$
We know that Robbie and Cameron combined have 3/7 of <span>Louis, Tom and Charlie combined. We can use this information to build our second equation.
</span> $R_o+C_a= \frac{3}{7} (L_o+T_o+C_h)$
$2x+k= \frac{3}{7} (x+2k+x+3k+x+4k)$
$2x+k= \frac{3}{7} (3x+9k)$
$14x+7k=9x+27k$
$5x=20k$
$x=4k$
Now this piece of information alows us to solve the first equation that we made and this will solve our problem. We simply plug in x=4k into 5x+10k=60.
$5(4k)+10k=60$
$30k=60$
$k=2$
Now we can plug this information into the same equation 5x+10k=60 and get x.
$5x+10(2)=60$
$5x=40$
$x=8$
And that's it. Now we can write out how many cookies each boy has bought.
$R_{o} : x=8$
$C_{a} : x+k=10$
$L_{o} : x+2k=12$
$T_{o} : x+3k=14$
$C_{h} : x+4k=16$
If you add them all up you get 60.

3 0

3 years ago

a) The average height of sunflowers in a field is 64 inches with a standard deviation of 3.5 inches. Describe a normal curve for

tresset_1 [31]

The values on the horizontal axis are:
at 0 = 64
at one standard deviation (lower, upper) = (60.5 , 67.5)
at two standard deviation (lower, upper) = (57 , 71)
at three standard deviation (lower, upper) = (53.5 , 74,5)

B. P(x > 71) = 1 - P(x < 71) = 1 - P[z < (71 - 64)/3.5] = 1 - P(z < 2) = 1 - 0.97725 = 0.02275
Therefore the no of plants taller than 71 inches will be approximately 0.02275 * 3000 = 68

8 0

3 years ago