Un numero entero y racional
1 answer:
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The picture in the attached figure
we know that
area of the <span>the shaded region=area of rectangle -area of a kite
area of rectangle=(3x+x)*(x+x)----> 4x*2x---> 8x</span>²
area of a kite=(1/2)*[d1*d2]
where d1 and d2 are the diagonals
d1=4x
d2=2x
so
area of a kite=(1/2)*[4x*2x]----> 4x²
area of the the shaded region=8x²-4x²-----> 4x²
the answer is
4x²
we know that
area of the <span>the shaded region=area of rectangle -area of a kite
area of rectangle=(3x+x)*(x+x)----> 4x*2x---> 8x</span>²
area of a kite=(1/2)*[d1*d2]
where d1 and d2 are the diagonals
d1=4x
d2=2x
so
area of a kite=(1/2)*[4x*2x]----> 4x²
area of the the shaded region=8x²-4x²-----> 4x²
the answer is
4x²
Answer:
Bouquets of roses = 20
Bouquets of carnations = 08
Step-by-step explanation:
Let,
x be the bouquets of roses sold
y be the bouquets of carnations sold
According to given statement;
x + y = 28 Eqn 1
16x + 10y = 400 Eqn 2
Multiplying Eqn 1 by 16
16(x+y=28)
16x + 16y = 448 Eqn 3
Subtracting Eqn 2 from Eqn 3
(16x+16y)-(16x+10y) = 448 - 400
16x + 16y - 16x - 10y = 48
6y = 48
Dividing both sides by 6
Putting y=8 in Eqn 1
x + 8 = 28
x = 28 - 8
x= 20
Hence,
Bouquets of roses = 20
Bouquets of carnations = 08