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Ivahew [28]
2 years ago
7

The graph shows the vertical displacement y, in inches, that a weight bouncing from a spring world achieve if there were no fric

tion, for the given number of seconds x,
What is the graph Frequency?


Question 1 options:


A. 1/3
B.1/6
C.6
D.12

Mathematics
1 answer:
marissa [1.9K]2 years ago
3 0

Answer:

Option B. \frac{1}{6}

Step-by-step explanation:

we know that

The frequency is equal to the number of cycles divided by the time

Remember that

1 cycle = 1 full wave to repeat itself

In this problem

From o to 12 seconds ------> there are 2 cycles

therefore

The frequency is equal to

f=\frac{2}{12}=\frac{1}{6}

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==================================

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\begin{gathered} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \tt{C = 2πr} \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \tt{226.08 = 2(3.14)\red{r}} \\ \\ \: \: \: \: \: \: \: \: \large \tt{ \frac{226.08}{6.28} = \cancel\frac{6.28 \red{r}}{6.28} } \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \boxed{\tt\green{C = 36}}\end{gathered}

C=2πr

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6.28

226.08

=

6.28

6.28r

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To check:

\begin{gathered} \small\begin{array}{|c|}\hline \bold{circumference }\\ \\ \tt{C = 2πr} \\ \tt{C = 2(3.14) (36\:cm) } \\ \tt{C = 2(113.04\:cm) } \\ \underline{\tt \green{C = 226.08\:cm }} \\ \hline \end{array} \end{gathered}

circumference

C=2πr

C=2(3.14)(36cm)

C=2(113.04cm)

C=226.08cm

FINAL ANSWER

If Mary's Bicycle has a circumference of 226.08 cm then the radius is 36.

\boxed{ \tt \red{r = 36}}

r=36

==================================

#CarryOnLearning

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