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musickatia [10]
3 years ago
6

A panel of 10 interviewers was to interview two candidates A and B to decide who was suitable for a job. 7 said A was suitable,

5 said B was suitable while 2 said neither A nor B was suitable. (i) How many said both A and B were suitable. (ii) How many said A alone was suitable.
Mathematics
1 answer:
Rzqust [24]3 years ago
7 0

Answer:

(i) 4 interviewers

(ii) 3 interviewers

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GenaCL600 [577]

ok, so, it's 12 ft by 17 ft but, because we want to leave a one foot space around the room, we should subtract 1 from each of the mesurments and then multiply those numbers

11 x 16 = 176

8 0
4 years ago
cam hits the bullseye in 8 darts out of 15 throws. what is the experimental probability that came next throws will hit the bulls
Zigmanuir [339]

Answer:

A darts player practices throwing a dart at the bull’s eye on a dart board. Her probability of hitting the bull’s eye for each throw is 0.2.

(a) Find the probability that she is successful for the first time on the third throw:

The number F of unsuccessful throws till the first bull’s eye follows a geometric

distribution with probability of success q = 0.2 and probability of failure p = 0.8.

If the first bull’s eye is on the third throw, there must be two failures:

P(F = 2) = p

2

q = (0.8)2

(0.2) = 0.128.

(b) Find the probability that she will have at least three failures before her first

success.

We want the probability of F ≥ 3. This can be found in two ways:

P(F ≥ 3) = P(F = 3) + P(F = 4) + P(F = 5) + P(F = 6) + . . .

= p

3

q + p

4

q + p

5

q + p

6

q + . . . (geometric series with ratio p)

=

p

3

q

1 − p

=

(0.8)3

(0.2)

1 − 0.8

= (0.8)3 = 0.512.

Alternatively,

P(F ≥ 3) = 1 − (P(F = 0) + P(F = 1) + P(F = 2))

= 1 − (q + pq + p

2

q)

= 1 − (0.2)(1 + 0.8 + (0.8)2

)

= 1 − 0.488 = 0.512.

(c) How many throws on average will fail before she hits bull’s eye?

Since p = 0.8 and q = 0.2, the expected number of failures before the first success

is

E[F] = p

q

=

0.8

0.2

= 4.

7 0
3 years ago
Read 2 more answers
Lines a and b are parallel. When they are cut by transversals, they form a triangle Parallel lines a and b are cut by transversa
lord [1]

Answer:

Therefore, the angle 3 have 28 degrees.

Step-by-step explanation:

We know that the lines a and b are parallel. When they are cut by transversals, they form a triangle. Parallel lines a and b are cut by transversals s and t to form a triangle. Angle 1 is 90 degrees, angle 2 is 62 degrees.

We know that the number of degrees in a triangle equals 180.

We get:

90+62+x=180\\\\152+x=180\\\\x=180-152\\\\x=28\\

Therefore, the angle 3 have 28 degrees.

6 0
4 years ago
Read 2 more answers
Perform the indicated operation. x/2+y/3-z/4
weeeeeb [17]

\bf \cfrac{x}{2}+\cfrac{y}{3}-\cfrac{z}{4}\implies \stackrel{\textit{using the LCD of 12}}{\cfrac{(6)x~~+~~(4)y~~-~~(3)z}{12}}\implies \cfrac{6x+4y-3z}{12}

3 0
3 years ago
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HELP ME PLEASE!!!!!!! Solve the triangles with the given information. (#1-5). (10 points each)
VashaNatasha [74]

so if they are triangles right u would add each sides

3 0
3 years ago
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