The probability that at least two of the missiles hit the arsenal:
P ( x ≥ 2 ) = P ( x = 2 ) + P ( x = 3 )
P ( x = 2 ) = 0.75 · 0.85 · 0.1 + 0.85 · 0.9 · 0.25 + 0.75 · 0.9 · 0.15 =
= 0.06375 + 0.10125 + 0.19125 = 0.35625
P ( x = 3 ) = 0.75 · 0.85 · 0.9 = 0.57375
P ( x ≥ 2 ) = 0.35625 + 0.57375 = 0.93
Answer:
The probability is 0.93 or 93%.
Answer:
The coordinates of B is (5,-2)
Step-by-step explanation:
In order to find the coordinates of B, you have to use midpoint formula. Then substitute the following values into the formula :

Let (x1,y1) be A (-3,-6),
Let (x2,y2) be B,
Let midpoint be M (1,-4),








Answer: A B
Group 1 0.25 0.75
Group 2 0.44 0.56
Step-by-step explanation:
Since we have given that
Number of people of A in group 1 = 15
Number of people of B in group 1 = 45
Total number of people in group 1 is given by

Relative frequency of people of A in Group 1 is given by

Relative frequency of people of B in Group 1 is given by

Similarly, Number of people of A in group 2 = 20
Number of people of B in group 2 = 25
Total number of people in group 2 is given by

Relative frequency of people of A in Group 2 is given by

Relative frequency of people of B in Group 2 is given by

Hence, A B
Group 1 0.25 0.75
Group 2 0.44 0.56
I'm assuming that you meant:
y = 7x² + 3
Remember! Inputs are always x values (unless stated otherwise). Meaning the problem says:
x = 4
y = 7(4)² + 3
The square only applies to the 4. The 7 is not going to be squared! (To be exact it only applies to whatever the value of x is.
4² = 4·4 = 16
Remember:
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction
Follow PEMDAS from left to right (or in the case above from top to bottom).
7·16 + 3 = ?
16·7 = 10·7 + 6·7 = 70 + 42 = 112
(All I did to multiply was break it up into parts. If it confuses you don't worry about it, and just multiply it out like normal or use a calculator if you are allowed to)
112 + 3 = ?
Our output is:
115!