24(3)+88(6)
24×3+88×6
72+528
=600
hope this help:)
It will take 7.5 hours for only 40% of the caffeine to remain in his body.
Step-by-step explanation:
Half-life (symbol t1⁄2) is the time required for a quantity to reduce to half of its initial value.
The half-life of caffeine is 5.7 hours.
It means that if we have 10 ounces of caffeine. After 5.7 hours, the remaining caffeine will be equal to 5 ounces and so on.
And the decaying speed depends on the initial amount of the substance.
In the given question.
t1⁄2 = 5.7 hours
Initial amount = N(i) = 16 ounces
Remaining amount after time t = N(t) = 40% of 16 = 6.4 ounces
time t = ?
Using the following formula for remaining amount of substance after time t:
N(t) = N(i)*(0.5)^(t/t1⁄2)
we can find the time t
putting the values in the formula given above, we get:
![6.4 = 16(\frac{1}{2} )^\frac{t}{5.7}\\ \frac{6.4}{16} = (0.5)^\frac{t}{5.7}\\ 0.4=(0.5)^\frac{t}{5.7}\\](https://tex.z-dn.net/?f=6.4%20%3D%2016%28%5Cfrac%7B1%7D%7B2%7D%20%29%5E%5Cfrac%7Bt%7D%7B5.7%7D%5C%5C%20%5Cfrac%7B6.4%7D%7B16%7D%20%3D%20%280.5%29%5E%5Cfrac%7Bt%7D%7B5.7%7D%5C%5C%200.4%3D%280.5%29%5E%5Cfrac%7Bt%7D%7B5.7%7D%5C%5C)
Taking natural log on both sides:
![ln(0.4) = ln(0.5)^\frac{t}{5.7}\\ln(0.4) = \frac{t}{5.7}(ln(0.5))\\t = \frac{ln(0.4)}{ln(0.5)}5.7\\t= 1.32*5.7\\t=7.5 hours](https://tex.z-dn.net/?f=ln%280.4%29%20%3D%20ln%280.5%29%5E%5Cfrac%7Bt%7D%7B5.7%7D%5C%5Cln%280.4%29%20%3D%20%5Cfrac%7Bt%7D%7B5.7%7D%28ln%280.5%29%29%5C%5Ct%20%3D%20%5Cfrac%7Bln%280.4%29%7D%7Bln%280.5%29%7D5.7%5C%5Ct%3D%201.32%2A5.7%5C%5Ct%3D7.5%20hours)
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Answer:
a
Step-by-step explanation:
Mode is the most frequent value in the data, if u equals 5 there will be two 5 which means 5 will become the mode.
The property illustrated is the Commutative Property