1. Parabola's equation is y = a(x + b)^2 + c, where (b, c) is the vertex.
2. We have y = a(x - 3)^2 + 1
3. Take everything to the left side:
-a(x - 3)^2 + y - 1 = 0
That's the standard equation. Hope this helps! :)
Answer:
nah its not cause in radical form that bih is 5√5
Step-by-step explanation:
<u>w</u><u>=</u><u>-</u><u>1</u><u>.</u><u>5</u>
<u>w</u><u>=</u><u>2</u>
Answer:
Solution given:

again
keep square root alone

solve subtraction of 7-2

Squaring on both side

2w²-19w+31=5²-2*5*2w+4w²
take terms one side
2w²-19w+31-25+20w-4w²=0
-2w²+w+6=0
2w²-w-6=0
doing middle term factorisation
2w²-(4-3)w-6=0
2w²-4w+3w-6=0
take common from each two term
2w(w-2)+3(w-2)=0
(w-2)(2w+3)=0
either
w=2
or
W=-3/2=-1.5
Answer:4
Step-by-step explanation:
<u>x² - 4x - 5</u> <u>x² - 3x - 10</u>
(x - 5)(x + 1) (x - 5)(x + 2)
GCF: (x - 5)
LCM: (x - 5)(x + 1)(x + 2)
Answer: (x - 5)(x + 1)(x + 2)