A scaled copy with the scale factor being 3/4 it would be smaller because it’s less than one so whenever there is a fraction that’s less than one then the shape would be smaller aswell
Answer:
x ∈ {-5, -1}
Step-by-step explanation:
Here's the solution using the quadratic formula:
The real zeros are -5 and -1.
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There are many ways to check your answer. One of them is to look at the given quadratic, which has no changes of sign in its coefficients. (They are all positive.) That means there can be no positive real roots, so already you know that x=0.5 won't work.
Also, the constant in the quadratic is the product of the roots, For your roots, their product is -7/4, so even multiplying by 4 (the leading coefficient in the given quadratic), you don't get anything like 20.
Hello there!
An equation to model this situation is 3n - 50 = -11
The unknown number has a value of 13.
Okay, so let's start by breaking down the question - we'll use <em>n</em> to model the unknown number.
-50 added to three times an unknown number equals -11?
This means we are adding -50 to something else. (We can use + -50 or - 50 since they are the same thing, I'll use - 50 since it's easier to follow.)
-50 added to three times an unknown number equals -11?
This phrase can be modeled as 3n. This is what we are taking 50 from, so we can add that to the end of the equation so far.
3n - 50
-50 added to three times an unknown number equals -11?
This can means the equation equals -11. We can model it as = -11. Now, let's add it to our equation.
3n - 50 = -11
Now, solve for n.
You want to start by canceling -50 out on the left side, so n is on it's own side, and to do this you add 50 to both sides.
3n - 50 + 50 = -11 + 50
3n = 39
To finish isolating n, divide both sides of the equation by 3.
3÷3n = 39÷3
n = 13.
I hope this helps and have a great day!
<span>The center, vertex, and focus all lie on the line y = 0. Then we know that the equation of a hyperbola is a^2 + b^2 = c^2 . a^2 represents the x part of the equation and the y part will be subtracted. We know that the vertex is 48 units from the center and that the focus is 50 units from the center. Then we have that b^2 = 2500 - 2304 = 196 .
Thus the equation that represents the hyperbola is x^2/2304 - y^2/196 = 1 or 49x^2 -576y^2 - 112896 = 0</span>
Answer:
B= 50
Step-by-step explanation:
