The answer:
the full question is as follow:
if A+B-C=3pi, then find sinA+sinB-sinC
first, the main formula of sine and cosine are:
sinC = 2sin(C/2)cos(C/2)
sinA +sinB = 2sin[(A+B)/2]cos[(A-B)/2]
therefore:
sinA+sinB-sinC = 2sin[(A+B)/2]cos[(A-B)/2] - 2sin(C/2)cos(C/2)
sin[(A+B)/2] = cos(C/2)
2sin(C/2)cos(C/2) = cos[(A+B)/2
and
A+B-C=3 pi implies A+B =3 pi + C, so
cos[(A+B)/2] = cos [3 pi/2 + C/2]
and with the equivalence cos (3Pi/2 + X) = sinX
sinA+sinB-sinC = cos(C/2)+ sin(C/2)
Hello!
The equation to find the volume of a cylinder is

V is volume
r is radius
h is height
Put in the values you know

Square the number

Multiply

The answer is

Hope this helps!
Answer:
B) one solution
Step-by-step explanation:
The blue line and the red line cross at only one point so there is one solution. It would be no solution if the blue line never crossed the red line and it would be two or possibly more solutions if the lines crossed more than once.
The product of 2 and 3 is 6. When you take away, or subtract, 5 from 6, you get 1.