Question

HELP ME FAST THAKS A MILLION PLEASE HELP

Answer 1

Answer:

b. 15.39 L

Step-by-step explanation:

Given;

reacting mass of the Nitrogen gas N₂, m = 42 g

pressure of the gas, P = 2 atm

temperature of the gas, T = 250 K

molar mass of Nitrogen, N = 14 g/mol

molar mass of Nitrogen gas N₂, M = 28 g/mol

number of moles of the given Nitrogen gas;

$n = \frac{Reacting \ mass}{Molar \ mass} = \frac{m}{M} \\\\n = \frac{42 \ g}{28 \ g/mol} = 1.5 \ mol.$

The volume occupied by the Nitrogen gas can be calculated from Ideal gas law;

PV = nRT

where;

V is the volume of the gas

R is ideal gas constant = 0.0821 atm.L / mol.K

From the equation above, make V the subject of the formula;

$V = \frac{nRT}{P} \\\\V = \frac{1.5\ mol. \ \times \ 0.0821 \ atm.L/mol.K \ \times \ 250 \ K}{2 \ atm} \\\\V = 15.39 \ L$

Therefore, the volume occupied by the Nitrogen gas is 15.39 L