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julsineya [31]
3 years ago
10

Help fast!!!!!!!!! Solve for X z=6 π x y

Mathematics
1 answer:
Serga [27]3 years ago
4 0
The answer is x=z/6<span>πy</span>
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Randall would like to purchase a pair of shoes that are regulary priced at $88. The store is running a 20% off sale. There is al
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The answer would be D.

Randall should choose the rebate offer because the shoes will be $2.40 less than if he chooses the sale price.

88 - 20% = 70.4

88 - 20 = 68

70.4 - 68 = 2.4 (2.40)

Please mark me brainliest! Thanks!

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2 years ago
Help pleasssseeee......(do all pls)
Ugo [173]
16. 5x^3 y^-5 • 4xy^3
20x^4y^-2

20x^4 • 1/y^2

=20x^4/y^2

17. -2b^3c • 4b^2c^2
= -8b^5c^3

18. a^3n^7 / an^4 (a^3 minus a = a^2 same as n^7 minus n^4 = n^3)
=a^2n^3

19. -yz^5 / y^2z^3

= -z^2/y

20. -7x^5y^5z^4 / 21x^7y^5z^2 (divide -7 to 21 and minus xyz)

= -z / 3x^2

21. 9a^7b^5x^5 / 18a^5b^9c^3

=a^2c^2 / 2b^4

22. (n^5)^4

n ^5 x 4
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23. (z^3)^6
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4 0
3 years ago
Read 2 more answers
Find the recipricol of -b/3
Licemer1 [7]

Answer:

-0.333333333

Step-by-step explanation:

7 0
2 years ago
If 1/3 of a set of numbers is 8 how many numbers are in the total set ?
Eduardwww [97]

Answer:

24

Step-by-step explanation:

1/3 = 8

3/3 = 8*3

7 0
2 years ago
Let v = (v1, v2) be a vector in R2. Show that (v2, −v1) is orthogonal to v, and use this fact to find two unit vectors orthogona
andrey2020 [161]

Answer:

a. v.v' = v₁v₂ -  v₁v₂ = 0 b.  (20, -21)/29 and  (-20,21)/29

Step-by-step explanation:

a. For two vectors a, b to be orthogonal, their dot product is zero. That is a.b = 0.

Given v = (v₁, v₂) = v₁i + v₂j and v' =  (v₂, -v₁) = v₂i - v₁j, we need to show that v.v' = 0

So, v.v' = (v₁i + v₂j).(v₂i - v₁j)

= v₁i.v₂i + v₁i.(- v₁j) + v₂j.v₂i + v₂j.(- v₁j)

= v₁v₂i.i - v₁v₁i.j + v₂v₂j.i - v₂v₁j.j

i.i = 1, i.j = 0, j.i = 0 and j.j = 1

So, v.v' = v₁v₂i.i - v₁v₁i.j + v₂v₂j.i - v₂v₁j.j  

= v₁v₂ × 1 - v₁v₁ × 0 + v₂v₂ × 0 - v₂v₁ × 1

= v₁v₂ - v₂v₁

=  v₁v₂ -  v₁v₂ = 0

So, v.v' = 0

b. Now a vector orthogonal to the vector v = (21,20) is v' = (20,-21).

So the first unit vector is thus a = v'/║v'║ = (20, -21)/√[20² + (-21)²] = (20, -21)/√[400 + 441] = (20, -21)/√841 = (20, -21)/29.

A unit vector perpendicular to a and parallel to v is b = (-21, -20)/29. Another unit vector perpendicular to b, parallel to a and perpendicular to v is thus a' = (-20,-(-21))/29 = (-20,21)/29

8 0
2 years ago
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