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Arisa [49]
3 years ago
13

I need to create a method named "root positive". which will either print the square root of the number passed to it or if the nu

mber is less than zero, it will print out the statement "Number must not be negative."?
1. Ask the user to input a number of type double which you will find the square root of the number.

2. Create a method called rootPositive which will either print the square root of the number passed to it or if the number is less than zero, it will print out the statement "Number must not be negative.".

3. Call your rootPositive method and pass to it the number the user enetered.
Computers and Technology
1 answer:
rjkz [21]3 years ago
5 0

Answer:

Explanation:

The following code is written in Java. It is a method that calculates the square root of a number as requested. The method first checks with an IF statement if the parameter value is a positive number and then calculates the square root and prints it to the screen. Otherwise, it prints Number must not be negative. A test case has been provided in the main method and the output can be seen in the attached image below.

import java.util.Scanner;

class Brainly {

   public static void main(String[] args) {

       Scanner in = new Scanner(System.in);

       System.out.print("Enter a number of type double to calculate square root:");

       double num = in.nextDouble();

       rootPositive(num);

   }

   public static void rootPositive(double num) {

       if (num > 0) {

           System.out.println(Math.sqrt(num));

       } else {

           System.out.println("Number must not be negative.");

       }

   }

}

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I'm using assembly language. This is my assignment. I kinda confused about how to write code for this assignment. Can anyone exp
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Answer:

oid changeCase (char char_array[], int array_size ) {

__asm{

   mov eax, char_array;    

   mov edi, 0;

readArray:

   cmp edi, array_size;

   jge exit;

   mov ebx, edi;          

   shl ebx, 2;

   mov cl, [eax + ebx];    

check:

   //working on it

   cmp cl, 0x41;      

   jl next_indx;

   cmp cl, 0x7A;      

   jg next_indx;

   cmp cl, 'a';

   jl convert_down;

   jge convert_up;

convert_down:

   or cl, 0x20;        //make it lowercase

   jmp write;

convert_up:

   and cl, 0x20;      

   jmp write;

write:

   mov byte ptr [eax + ebx], cl    

next_indx:

   inc edi;

exit:

   cmp edi, array_size;

   jl readArray;

mov char_array, eax;

}

}

Explanation:

  • Move char_array to eax as it is base image .
  • Use ebx as offset .
  • Use ecx as the storage register .
  • check if cl is <= than ASCII value 65 (A) .
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