Given that in a trianlgle the sides AB, BC, CA are in the ratio 3:4:6.
Let AB = 3k, BC = 4k and CA = 6k.
Then perimeter =3k+4k+6k = 13k
M, N, K are mid points of the sides.
By mid point theorem MN = 3k/2, NK = 4k/2 and KM = 6k/2
Hence perimeter of MNK = 13k/2 =5.2 (given)
Solve for k
k=2(5.2)/13 = 0.8
Hence sides are
AB = 3k = 3(0.8) = 2.4 in
BC = 4k= 3.2 in
CA = 4.8 in
Answer:
y = mx + b
Step-by-step explanation:
Use that form to find the slope.
Find the <u>vertical </u>and <u>horizontal</u> <u>asymptotes</u> of the <u>graph</u> of the <u>function</u> 
1. Vertical asymptote.
Since the denominator of the fraction is 
then the vertical asymptote is 
because the domain of the function is 
2. Horizontal asymptote.
Rewrite the function f(x):
The horizontal asymptote has the equation 
Answer: correct choice is B
The absolute value of -32 is greater than the absolute value of -23
Answer:
Step-by-step explanation:
Sustituye la variable
y
con
|
x
−
3
|
+
|
x
+
2
|
−
|
x
−
5
|
en la expresión.
s
i
−
2
