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3 years ago

If a gold ring has a sale price of $21, what was the original price?

Mathematics

2 answers:

Schach [20]3 years ago

3 0

Answer:

27.30

Step-by-step explanation:

Alexandra [31]3 years ago

3 0

It would be 70 originally because when u turn 30% into a decimal it would be .3 and so u now divide 21 by .3 and get the answer of $70

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AB is a tangent. Find the length of the radius, r.

Lena [83]

Answer: 8

Step-by-step explanation:

Since AB is a tangent, angle CAB is a right angle. Thus, by the Pythagorean theorem, $r=\sqrt{17^{2}-15^{2}}=8$

4 0

2 years ago

A drama class has a total of

Alecsey [184]

42-14= 28
28÷2=14
answer: there are 14 females in the class and 28 males in the class

Check:14+28=42

5 0

4 years ago

Read 2 more answers

What's the equivalent

olga2289 [7]

9 1/2 = 19/2

(29/5) / (19/2)

When changing division to multiplication, flip the number (right hand side).

(29/5) * (2/19)

58/95

7 0

3 years ago

Can someone please explain this to me? Thanks!

Makovka662 [10]

Answer: Choice D

$\displaystyle F\ '(x) = 2x\sqrt{1+x^6}\\\\$

==========================================================

Explanation:

Let g(t) be the antiderivative of $g'(t) = \sqrt{1+t^3}$ . We don't need to find out what g(t) is exactly.

Recall by the fundamental theorem of calculus, we can say the following:

$\displaystyle \int_{a}^{b} g'(t)dt = g(b)-g(a)$

This theorem ties together the concepts of integrals and derivatives to show that they are basically inverse operations (more or less).

So,

$\displaystyle F(x) = \int_{\pi}^{x^2}\sqrt{1+t^3}dt\\\\ \displaystyle F(x) = \int_{\pi}^{x^2}g'(t)dt\\\\ \displaystyle F(x) = g(x^2) - g(\pi)\\\\$

From here, we apply the derivative with respect to x to both sides. Note that the $g(\pi)$ portion is a constant, so $g'(\pi) = 0$

$\displaystyle F(x) = g(x^2) - g(\pi)\\\\ \displaystyle F \ '(x) = \frac{d}{dx}[g(x^2)-g(\pi)]\\\\\displaystyle F\ '(x) = \frac{d}{dx}[g(x^2)] - \frac{d}{dx}[g(\pi)]\\\\ \displaystyle F\ '(x) = \frac{d}{dx}[x^2]*g'(x^2) - g'(\pi) \ \text{ .... chain rule}\\\\$

$\displaystyle F\ '(x) = 2x*g'(x^2) - 0\\\\ \displaystyle F\ '(x) = 2x*g'(x^2)\\\\ \displaystyle F\ '(x) = 2x\sqrt{1+(x^2)^3}\\\\ \displaystyle F\ '(x) = \boldsymbol{2x\sqrt{1+x^6}}\\\\$

Answer is choice D

5 0

2 years ago

Read 2 more answers

Problem #7 PLEASE HELP ;(

mixer [17]

Answer:

Yes

6(x+0.4) is equivalent to 3(2x+0.8)

Step-by-step explanation:

Given in the questions two expressions

6(x + 0.4)

3(2x + 0.8)

We will apply distributive law

It is a law relating the operations of multiplication and addition, stated symbolically

6(x + 0.4)

= 6(x) + 6(0.4)

= 6x + 2.4

3(2x + 0.8)

= 3(2x) + 3(0.8)

= 6x + 2.4

Since both equations when expanded have same answers, hence they are equivalent

4 0

3 years ago