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Alisiya [41]
3 years ago
14

EXPERTS/ACE/GENIUSES/TRUSTED HELPERS HELPP ME

Mathematics
1 answer:
PilotLPTM [1.2K]3 years ago
8 0

17.76(5) = 88.15 + 27.52 = 115.67


 Answer is A

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Solve for u.<br> 3x u = 12
koban [17]
U=4 because 3 x 4 is equal to 12
7 0
3 years ago
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HELP!! Select the values for the domain and range of the functions graphed below.
Goryan [66]

Answer:

Graph 1

Domain = -8 =< x =< 10

Range = -9 =< f(x) =< 9

Graph 2

Domain = -1 =< x =< 5

Range = -1 =< f(x) =< 2

Explaination:

Domain means the inputed x values on the x-axis, so to make things simpler and to not write every individual x values. We write it with <, >, and =<. (you can see it as the 'width' of a graph).

Range means the output y values on the y-axis. It's like the 'height' of a graph. And also, to make things simpler and to not write every individual y values. We write it with <, >, and =< with f(x) too because f(x) = y.

3 0
2 years ago
Need help please...........
Katen [24]
The missing angle is 49 :)
8 0
2 years ago
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What does y equal ??!?!
garik1379 [7]
<h3>Answer:  658.3</h3>

==================================================

Explanation:

The adjacent complementary angle to that 28 degree angle is 62 degrees because 62+28 = 90.

If the reference angle is the upper acute angle 62 degrees, then the y is the opposite leg and the side 350 is the adjacent leg.

Use the tangent ratio

tan(angle) = opposite/adjacent

tan(62) = y/350

350*tan(62) = y

y = 350*tan(62)

y = 658.254262871217

y = 658.3

3 0
3 years ago
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two buses leave towns 604 mi apart at the same time and travel toward eachother. One bus travels 9 mi/h faster than the other on
muminat

Answer:

s = 71 mph, and s+9 = f = 80 mph

Step-by-step explanation:

The distances the two busses travel add up to 604 mi.

Letting f be the faster speed and s the slower.  Then f = s + 9 (mph).

Then (s + 9)(mph)(4 hr) + (s)(mph)(4 hr) = 604 mi.  Solve this for s:

4s + 36 + 4s = 604 mi, or 8s = 568.  Finally, s = 71 mph, and s+9 = f = 80 mph.


3 0
3 years ago
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