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3 years ago

Side length 6cm ,6cm, 4cm. How many different triangles can you make ?

Mathematics

2 answers:

umka21 [38]3 years ago

8 0

2 different triangles

Klio2033 [76]3 years ago

7 0

Answer:

Technically, one (they equal the same thing) but 2 in this case.

Step-by-step explanation:

6 + 6 + 4

6 + 4 + 6

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Answer: Nice words my guy

Step-by-step explanation:

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3 years ago

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If y varies directly as x, and y is 12 when x is 1.2, what is the constant of variation for this relation?

laila [671]

If you multiply 12 by 0.1, you get 1.2. To write this as a function you would say y is x multiplied by 0.1.
y=0.1x

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3 years ago

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In ΔUVW, w = 44 cm, u = 83 cm and ∠V=141°. Find the area of ΔUVW, to the nearest square centimeter.

Tema [17]

Answer:

$Area \approx 1149\ cm^2$

Step-by-step explanation:

<u>Given that:</u>

ΔUVW,

Side w = 44 cm, (It is the side opposite to $\angle W$ )

Side u = 83 cm (It is the side opposite to $\angle U$ )

and ∠V=141°

Please refer to the attached image with labeling of the triangle with the dimensions given.

Area of a triangle with two sides given and angle between the two sides can be formulated as:

$A = \dfrac{1}{2}\times a\times b\times sinC$

Where a and b are the two sides and

$\angle C$ is the angle between the sides a and b

Here we have a = w = 44cm

b = u = 44cm

and ∠C= ∠V=141

Putting the values to find the area:

$A = \dfrac{1}{2}\times 44\times 83\times sin141\\\Rightarrow A = \dfrac{1}{2} \times 3652 \times sin141\\\Rightarrow A =1826 \times 0.629\\\Rightarrow A \approx 1149\ cm^2$

So, the <em>area </em>of given triangle to the nearest square centimetre is:

$Area \approx 1149\ cm^2$

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4 years ago

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Hunter-Best [27]

Answer:

no time left sorry

Step-by-step explanation:

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3 years ago

Seeds are often treated with fungicides to protect them in poor-draining, wet environments. A small-scale trial, involving six t

alukav5142 [94]

Answer:

0.0076 = 0.76% probability that all five plants emerged from treated seeds

Step-by-step explanation:

The plants were chosen without replacement, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

In this question:

6 + 6 = 12 seeds, which means that $N = 12$

6 treated, which means that $k = 6$

Five sprouted, which means that $n = 5$

What is the probability that all five plants emerged from treated seeds?

This is P(X = 5). So

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

$P(X = 5) = h(5,12,5,6) = \frac{C_{6,5}*C_{6,0}}{C_{12,5}} = 0.0076$

0.0076 = 0.76% probability that all five plants emerged from treated seeds

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3 years ago