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Margaret [11]
3 years ago
6

Side length 6cm ,6cm, 4cm. How many different triangles can you make ?

Mathematics
2 answers:
umka21 [38]3 years ago
8 0
2 different triangles
Klio2033 [76]3 years ago
7 0

Answer:

Technically, one (they equal the same thing) but 2 in this case.

Step-by-step explanation:

6 + 6 + 4

6 + 4 + 6

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I know life can get hard but don't give up no matter what happens, because you never get anything out of quitting, but you get t
ss7ja [257]

Answer: Nice words my guy

Step-by-step explanation:

8 0
3 years ago
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If y varies directly as x, and y is 12 when x is 1.2, what is the constant of variation for this relation?
laila [671]
If you multiply 12 by 0.1, you get 1.2.   To write this as a function you would say y is x multiplied by 0.1.
y=0.1x
6 0
3 years ago
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In ΔUVW, w = 44 cm, u = 83 cm and ∠V=141°. Find the area of ΔUVW, to the nearest square centimeter.
Tema [17]

Answer:

Area  \approx 1149\ cm^2

Step-by-step explanation:

<u>Given that:</u>

ΔUVW,

Side w = 44 cm, (It is the side opposite to \angle W)

Side u = 83 cm (It is the side opposite to \angle U)

and ∠V=141°

Please refer to the attached image with labeling of the triangle with the dimensions given.

Area of a triangle with two sides given and angle between the two sides can be formulated as:

A = \dfrac{1}{2}\times a\times b\times sinC

Where a and b are the two sides and

\angle C is the angle between the sides a and b

Here we have a = w = 44cm

b = u = 44cm

and ∠C= ∠V=141

Putting the values to find the area:

A = \dfrac{1}{2}\times 44\times 83\times sin141\\\Rightarrow A = \dfrac{1}{2} \times 3652 \times sin141\\\Rightarrow A =1826 \times 0.629\\\Rightarrow A  \approx 1149\ cm^2

So, the <em>area </em>of given triangle to the nearest square centimetre is:

Area  \approx 1149\ cm^2

8 0
4 years ago
Can someone please solve FAST I have 5 minutes
Hunter-Best [27]

Answer:

no time left sorry

Step-by-step explanation:

7 0
3 years ago
Seeds are often treated with fungicides to protect them in poor-draining, wet environments. A small-scale trial, involving six t
alukav5142 [94]

Answer:

0.0076 = 0.76% probability that all five plants emerged from treated seeds

Step-by-step explanation:

The plants were chosen without replacement, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

In this question:

6 + 6 = 12 seeds, which means that N = 12

6 treated, which means that k = 6

Five sprouted, which means that n = 5

What is the probability that all five plants emerged from treated seeds?

This is P(X = 5). So

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

P(X = 5) = h(5,12,5,6) = \frac{C_{6,5}*C_{6,0}}{C_{12,5}} = 0.0076

0.0076 = 0.76% probability that all five plants emerged from treated seeds

3 0
3 years ago
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