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NeX [460]
3 years ago
8

Identify any extraneous solution. See above pic

Mathematics
2 answers:
yulyashka [42]3 years ago
5 0

D:z\geq 0\wedge z+5\geq 0\\D:z\geq 0\wedge z\geq -5\\D:z\geq0\\\\1+\sqrt z=\sqrt{z+5}\\1+2\sqrt z+z=z+5\\2\sqrt z=4\\\sqrt z=2\\z=4

4\in D so there are no extraneous solutions.

Sav [38]3 years ago
4 0

Answer:

There are no extraneous solutions

Reasoning:

An extraneous solution is a solution that isn't valid, it might be imaginary like the square root of a negative number.

first we want to isolate z:

1+sqrt(z)=sqrt(z+5)

^2 all      ^2 all

(1+sqrt(z))(1+sqrt(z))=z+5

expand

1+2sqrt(z)+z=z+5

-1              -z  -z -1

2sqrt(z)=4

/2           /2

sqrt(z)=2

^2 all    ^2 all

z=4

Since there is one solution and it is a real number, there are no extraneous solutions.

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Marcos purchased a sail boat for $56,900. He anticipates each year the boat will decrease in value by 8.1% from the previous yea
Varvara68 [4.7K]

Answer: 56,900\left( 0.919\right)^x

Step-by-step explanation:

Given

Marcos purchased a sailboat for \$56,900

Each year the boat will decrease in value by 8.1\%

After 1 year it is

\Rightarrow 56,900-56,900\times 0.081\\\Rightarrow 56,900\left( 1-0.081\right)\\

after another year it becomes

\Rightarrow 56,900\left( 1-0.081\right)-56,900\left( 1-0.081\right)\times 0.081\\\Rightarrow 56,900\left( 1-0.081\right)\cdot \left( 1-0.081\right)\\\Rightarrow 56,900\left( 1-0.081\right)^2

After x years it is

\Rightarrow 56,900\left( 1-0.081\right)^x

\Rightarrow 56,900\left( 0.919\right)^x

5 0
2 years ago
Yesterday, Audrey drank the liquids shown in the
Andrew [12]

Answer:

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if you add it all together

8 0
3 years ago
Read 2 more answers
Please help me with 10-12 +BONUS
dedylja [7]
Hi!

10.

This question is basically asking you, 10 is 40% of what number?

10 × 100 / 40 = 25

Fred must do 25 math problems.

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4 0
3 years ago
∆ABC transforms to produce ∆A'B'C'. Which transformation did NOT take place?
never [62]

Answer: The answer is (D) Reflection across the line y = -x.


Step-by-step explanation:  In figure given in the question, we can see two triangles, ΔABC and ΔA'B'C' where the second triangle is the result of transformation from the first one.

(A) If we rotate ΔABC 180° counterclockwise about the origin, then the image will coincide with ΔA'B'C'. So, this transformation can take place here.

(B) If we reflect ΔABC across the origin, then also the image will coincide with ΔA'B'C' and so this transformation can also take place.

(C) If we rotate ΔABC through 180° clockwise about the origin, the we will see the image will be same as ΔA'B'C'. Hence, this transformation can also take place.

(D) Finally, if we reflect ΔABC across the line y = -x, the the image formed will be different from ΔA'B'C', in fact, it is ΔA'D'E', as shown in the attached figure. So, this transformation can not take place here.

Thus, the correct option is (D).


6 0
2 years ago
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12x - 10<br><br> 2(6x - 5)<br><br> 2(x - 5) <br><br> 12 (x - 2)<br><br> -2(6x + 5)
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Answer:

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