Suppose one of the roots is a the second is 2a. The factors will be:
(x-a) and (x-2a)
thus
(x-a)(x-2a)=x^2+6x+q
x^2-xa-2ax+2a^2=x^2+6x+q
taking corresponding terms we shall have:
-2ax=6x
solving for a we get
-2a=6
thus
a=-3
but
q=2a^2
substituting the value of a we get:
q=2(-3)^2
q=2*9
q=18
1. lines j and k because they have the same slope.
2.d because -1/3 is the opposite slope of 3 and it passes through that point.
Answer:
It would be to ask all the students in the grade.
Step-by-step explanation:
