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trapecia [35]
3 years ago
9

Drag each equation to the correct location on the table.

Mathematics
2 answers:
statuscvo [17]3 years ago
5 0

Answer:

a = 1 will have.

2a + 3 < 9 - 3a.  

2a + 3 > 10 -3a.  

3a - 2a + 1>2.

a = 2 will have

ANY others I did not include in a = 1

Ket [755]3 years ago
4 0

Answer:

Hi! I hope this is correct please inform me if this is incorrect :)

a = 1 will have.

2a + 3 < 9 - 3a.  

2a + 3 > 10 -3a.  

3a - 2a + 1>2.

a = 2 will have

ANY others I did not include in a = 1 :)

Please once again tell me if this is incorrect.

Step-by-step explanation:

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Solve the system algebraically.<br> y = – 4x + 6<br> y = – 4x + 5
Nana76 [90]

Answer:

We conclude that -1 = 0 is false, therefore the system of equations has no solution.

Step-by-step explanation:

Given the system of equations

y = – 4x + 6

y = – 4x + 5

solving the system of the equations

\begin{bmatrix}y=-4x+6\\ y=-4x+5\end{bmatrix}

Substitute y = -4x+5

\begin{bmatrix}-4x+5=-4x+6\end{bmatrix}

Refine – 4x + 5 = – 4x + 6

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FALSE!

NO SOLUTION!

We conclude that -1 = 0 is false, therefore the system of equations has no solution.

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