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Juli2301 [7.4K]
3 years ago
12

Just need Answers on my late math homework

Mathematics
1 answer:
riadik2000 [5.3K]3 years ago
8 0

Answer:

Step-by-step explanation:

Where's the problem/question?

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Please hurry i need help and im stuck!!! helpsosososos
sammy [17]

Answer:

2

Step-by-step explanation:

the x and y are being multiplied by 2 e.g. 1 × 2 is 2 and 2 × 2 is 4 so the constant is 2

7 0
3 years ago
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Quizizz thx 10 pts each brainiest guaranteed with pic
Gre4nikov [31]

Answer:

option B

polynomial cannot have negative power

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7 0
3 years ago
A lab orders a shipment of 100 rats a week for experiments that the lab conducts. Prices for each weekly shipment of rats follow
Korolek [52]

Answer:

Therefore, the budget is 656.76$.

Step-by-step explanation:

We know that a lab orders a shipment of 100 rats a week for experiments that the lab conducts. Suppose the mean cost of the rats turned out to be $ 12.63 per week. We calculate budget of a lab for the next year's.

We know that 1 year have 52 weeks. We get

52 · 12.63 = 656.76

Therefore, the budget is 656.76$.

4 0
3 years ago
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Janet deposited $9,600 into an account that pays 4.4 interest, compounded daily. At the end of nine months, how much interest ha
neonofarm [45]

bearing in mind that 9 months is not even a year, but since there are 12 months in a year, then 9 months is really 9/12 years.


\bf ~~~~~~ \stackrel{\textit{daily}}{\textit{Continuously}} \textit{Compounding Interest Earned Amount} \\\\ A=Pe^{rt}\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill & \$9600\\ r=rate\to 4.4\%\to \frac{4.4}{100}\dotfill &0.044\\ t=years\to \frac{9}{12}\dotfill &\frac{3}{4} \end{cases} \\\\\\ A=9600e^{0.044\cdot \frac{3}{4}}\implies A=9600e^{0.033}\implies A\approx 9922.09 \\\\\\


\bf \stackrel{\textit{interest earned}}{9922.09-9600\implies 322.09}

5 0
3 years ago
Find the 2nd term of an arithmetic sequence with t5 = 3 and t7 = 7?
svetlana [45]
Let a be the first term and d be the common difference

t5 = 3 = a + 4d
t7 = 7 = a + 6d

a + 6d - a - 4d = 7 - 3
2d = 4
d = 2

Sub d = 2,
3 = a + 4(2)
a = -5

t2 = a + d
t2 = -5 + 2
t2 = -3
6 0
3 years ago
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