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zhannawk [14.2K]
3 years ago
15

The school buses at a middle school each hold 38 students. The school has, b, buses.

Mathematics
1 answer:
mel-nik [20]3 years ago
8 0

Answer:

38bs

Step-by-step explanation:

multiply the number of students that each bus can hold by the no of buses 38s×b=38bs

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Kaylee invested $860 in an account paying an interest rate of 6 1/8% compounded annually. Gabriel invested $860 in an account pa
gogolik [260]

Answer:

$2415

Step-by-step explanation:

Compound interest :

A = P(1 + r/n)^nt

n = number of compounding times per period

A = final amount ; P = initial investment

For account compounded continuously :

A = Pe^it

i = interest ; t number of years ;

Gabriel:

P = $860 ; i = 6 1/2 % = 13/2% = 0.065

When P triples ; A = 860 * 3 = 2580

2580 = 860*e^0.065t

2580/860 = e^0.065t

3 = e^0.065t

Take In

In(3) = 0.065t

1.0986122 = 0.065t

t = 1.0986122 / 0.065

t = 16.90 years

Kaylee's account at t = 16.90 years

Number of months = 16. 9 * 12 = 202.8 = 203

Rate = 6 1/8% = 6.125% = 0.06125

A = 860(1 + 0.06125 / 12)^202.8

A = 860(1 + 0.0051041) ^202.8

A = 860(1.0051041)^202.8

A = 860 * 2.8080176

A = 2414.8951

A = $2415

5 0
2 years ago
What is the circumference of the circle that has a radius of 8.6mm
liraira [26]

Answer:

C= 54.O4

.................

7 0
3 years ago
3^4+9 what is the value of the expression below
k0ka [10]
81+9=90 that is the answer. Hope it helped
5 0
3 years ago
Read 2 more answers
Determine the midpoint of the segment with endpoints (–10, –11) and (8, –17).
nataly862011 [7]

Answer:

Midpoint: (-1, -14)

6 0
3 years ago
Guys can you please help me I’m stuck
enot [183]

Answer:

The graph of the ellipse is shown in the attachment

vertices; ( -5,0) and (5,0)

co-vertices; (0, -2) and (0, 2)

foci; (\sqrt{21},0), (-\sqrt{21},0)

Step-by-step explanation:

The vertices and co-vertices of the ellipse are on the graph. They represent the turning points of the ellipse.

To determine the foci of the ellipse we write the given equation in standard form by dividing both sides by 100 and then simplifying;

\frac{x^{2} }{25}+\frac{y^{2} }{4}=1

We then determine the distance c from the center to the focus;

c^{2}=a^{2}-b^{2}

c=\sqrt{25-4}=\sqrt{21}

The foci of the ellipse are thus; (\sqrt{21},0), (-\sqrt{21},0)

3 0
3 years ago
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