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3 years ago

The school buses at a middle school each hold 38 students. The school has, b, buses.

Mathematics

1 answer:

mel-nik [20]3 years ago

8 0

Answer:

38bs

Step-by-step explanation:

multiply the number of students that each bus can hold by the no of buses 38s×b=38bs

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Each hat cost $9. Each scarf cost $4 less than each hat. What is the total for 7 hats and 9 scarves? Write a number sentence for

Sladkaya [172]

9xh = total cost of the hat
9 per hat - 4 = $5 each scarf

h = hat
s = scarf
(9xh) + (5x s)
(9x7) + (5x9) = 108

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3 years ago

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bazaltina [42]

Answer:

924m^3 is the volume of the rectangular prism

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Bought three boxes totaling 151 book cost 50% more than the other two what was the price of the more expensive book 80 85 90 95

GenaCL600 [577]

Two cheaper books = x
more expensive = 1.5x
so, 2.5x=150
150/2.5=x=60
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3 years ago

A new car is purchased for 25000 dollars. The value of the car depreciates at 8.25% per year. What will the value of the car be

inysia [295]

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98700

Step-by-step explanation:

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3 years ago

Triangle ABC has vertices at A(-2,1), B(-2,-3), and C(1,-2). What is the area of the triangle? a 18 square units b 9 square unit

natka813 [3]

Answer:

Option C. 6 square units

Step-by-step explanation:

we know that

Heron's Formula is a method for calculating the area of a triangle when you know the lengths of all three sides.

Let

a,b,c be the lengths of the sides of a triangle.

The area is given by:

$A=\sqrt{p(p-a)(p-b)(p-c)}$

where

p is half the perimeter

p= $\frac{a+b+c}{2}$

we have

Triangle ABC has vertices at A(-2,1), B(-2,-3), and C(1,-2)

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

step 1

Find the distance AB

$d=\sqrt{(-3-1)^{2}+(-2+2)^{2}}$

$d=\sqrt{(-4)^{2}+(0)^{2}}$

$dAB=4\ units$

step 2

Find the distance BC

$d=\sqrt{(-2+3)^{2}+(1+2)^{2}}$

$d=\sqrt{(1)^{2}+(3)^{2}}$

$dBC=\sqrt{10}\ units$

step 3

Find the distance AC

$d=\sqrt{(-2-1)^{2}+(1+2)^{2}}$

$d=\sqrt{(-3)^{2}+(3)^{2}}$

$dBC=\sqrt{18}\ units$

step 4

$a=AB=4\ units$

$b=BC=\sqrt{10}\ units$

$c=AC=\sqrt{18}\ units$

Find the half perimeter p

p= $\frac{4+\sqrt{10}+\sqrt{18}}{2}=5.70\ units$

Find the area

$A=\sqrt{5.7(5.7-4)(5.7-3.16)(5.7-4.24)}$

$A=\sqrt{5.7(1.7)(2.54)(1.46)}$

$A=\sqrt{35.93}$

$A=6\ units^{2}$

7 0

3 years ago