3 years ago

What is the initial value of the function: f(x)=3/2(2)^x

2 answers:

7 0

Answer:

the initial value -- f(0) -- results in a value of 1.5

Step-by-step explanation:

f(0) = $\frac{3}{2}$ · $2^{x}$ (any value raised to the power of zero equals one)

f(0) = $\frac{3}{2}$ · 1

f(0) = 3/2 or 1.5

3 0

It’s NONE. You can use symbolab

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