Answer:
0.7422 = 74.22% of scores are above 74.
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

Calculate the proportion of scores above 74.
This is 1 subtracted by the pvalue of Z when X = 74. So



has a pvalue of 0.2578
So 1-0.2578 = 0.7422 = 74.22% of scores are above 74.
Answer:
Step-by-step explanation:
Factors
- A term in multiplication for an entire variety by which a bigger complete quantity may be divided
- A divisor is an integer that evenly divides a range without leaving the rest
- Factorization is the decomposition of an item right into a product of other objects
- Integer factorization, the manner of breaking down a composite quantity into smaller non-trivial divisors
- A coefficient, a multiplicative thing in an expression, usually more than a few
- The act of forming a component institution or quotient ring in summary algebra
- A von Neumann algebra, with a trivial center
- Factor (graph principle), a spanning subgraph
- Any finite contiguous sub-sequence of a word in a group concept
(b)/(7.8)=-2.15
Multiply each term in the equation by 7.8.
(b)/(7.8)*7.8=-2.15*7.8
Cancel the common factor of (1)/(7.8).
1b=-2.15*7.8
Multiply -2.15 by 7.8 to get -16.77.
1b=-16.77
Divide each term in the equation by 1.
(1b)/(1)=-(16.77)/(1)
Cancel the common factor of 1.
b=-(16.77)/(1)
Divide -16.77 by 1 to get -16.77.
b=-16.77
#SPJ10
It is implied from the given conditions that
Unmarried employees = 45
Unmarried employees that work full time = 30
Part time working employees = 25
Unmarried employees that work part time = 15
Married employees that work part time = 10
Thus
The probability of a part time employee = 25/85
The probability of an unmarried employee = 45/85
Hence probability that an employee works part
time or is not married = (25/85) + (45/85)
= (25 + 45) / 85
<span>= 70 / 85</span>