What is the initial value of the function: f(x)=3/2(2)^x

Mathematics

2 answers:

Marina CMI [18]2 years ago

7 0

Answer:

the initial value -- f(0) -- results in a value of 1.5

Step-by-step explanation:

f(0) = $\frac{3}{2}$ · $2^{x}$ (any value raised to the power of zero equals one)

f(0) = $\frac{3}{2}$ · 1

f(0) = 3/2 or 1.5

Musya8 [376]2 years ago

3 0

It’s NONE. You can use symbolab

You might be interested in

Find the values of a and b so that the solution of the linear system is (-9,1).

Diano4ka-milaya [45]

Answer:

Step-by-step explanation:

we can write -9 instead of x and y=1 instead of 1

so we write solution again

-9a+1b=-31

-9a-1b=-41

-18a=-72

a=4

we should write 4 instead of a

-9(4)+1b=-31

-36+b=-31

b=5

a=4

6 0

2 years ago

Maya deposits $5000 into a checking account that pays 0.75% annual interest compounded monthly. What will be the balance after 8

Nana76 [90]

$~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$5000\\ r=rate\to 0.75\%\to \frac{0.75}{100}\dotfill &0.0075\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{monthly, thus twelve} \end{array}\dotfill &12\\ t=years\dotfill &8 \end{cases} \\\\\\ A=5000\left(1+\frac{0.0075}{12}\right)^{12\cdot 8}\implies A=5000(1.000625)^{96}\implies A\approx 5309.08$