Given: AB || CD If the coordinates of point A are (8, 0) and the coordinates of point B are (3, 7), the y-intercept of AB is . I
f the coordinates of point D are (5, 5), the equation of line CD is y = x + .
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In the parallelogram ABCD, join BD.
Consider the triangle Δ ABD.
It is given that AB > AD.
Since, in a triangle, angle opposite to longer side is larger, we have,
∠ ADB > ∠ ABD. --- (1)
Also, AB || DC and BD is a transversal.
Therefore,
∠ ABD = ∠ BDC
Substitute in (1), we get,
∠ ADB > ∠ BDC.
