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Travka [436]
3 years ago
7

Given two angles in each triangle, how can you determine if two triangles are similar?​

Mathematics
2 answers:
goldenfox [79]3 years ago
7 0

Answer:

If two pairs of corresponding angles in a pair of triangles are congruent, then the triangles are similar. We know this because if two angle pairs are the same, then the third pair must also be equal. When the three angle pairs are all equal, the three pairs of sides must also be in proportion.

Step-by-step explanation:

can you please mark me as brainliest

Mnenie [13.5K]3 years ago
3 0

Answer: To determine similarity, find the missing measure using the interior angle sum of a triangle. Then compare corresponding angles. If two pairs of angles are congruent, the triangles are similar because of the angle-angle criterion.

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What is the formula for sugar?​
Darina [25.2K]

Answer:

Almost all sugars have the formula CnH2nOn (n is between 3 and 7).

Step-by-step explanation:

5 0
3 years ago
Use vectors to find the interior angles of the triangle with the given vertices. (Enter your answers as a comma-separated list.
SOVA2 [1]

Answer:

23.92°, 78.503°, and 77.577°

Step-by-step explanation:

The coordinates of the vertices of the triangle are;

X(-3, -5), Y(2, 6), Z(6, 3)

The vectors are;

z = \left \langle 2 - (-3), 6 - (-5) \right \rangle = \left \langle 5, 11  \right \rangle

y = \left \langle 6 - (-3), 3 - (-5)  \right \rangle = \left \langle 9, 8 \right \rangle

x = \left \langle 2 - 6, 6 - 3  \right \rangle = \left \langle -4, 3  \right \rangle

cos (\alpha ) = \dfrac{z \cdot y}{\left |  z \right | \times \left | y  \right |}

Therefore, we get;

cos (\alpha ) = \dfrac{5 \times 9  + 11 \times 8 }{\left |  \sqrt{5^2 + 11^2}  \right | \times \left | \sqrt{9^2 + 8^2}   \right |} = \dfrac{133}{\sqrt{146} \times \sqrt{145} } \approx 0.91409

α = arccos(0.91490) ≈ 23.92°

γ = The angle between -y and x

-y = \left \langle -9, -8 \right \rangle

We get;

cos (\gamma) = \dfrac{-y \cdot x}{\left |  -y \right | \times \left | x  \right |}

Therefore;

cos (\gamma) = \dfrac{-9 \times -4  + -8 \times 3 }{\left |  \sqrt{(-9)^2 + (-8)^2}  \right | \times \left | \sqrt{(-4)^2 + 3^2}   \right |} = \dfrac{12}{\sqrt{145} \times \sqrt{25} } \approx 0.199309

γ = arccos(0.199309) ≈ 78.503°

γ ≈ 78.503°

By angle sum property, β = 180° - (α + β)

β ≈ 180° - (23.92° + 78.503°) = 77.577°

β ≈ 77.577°

The interior angles are;

23.92°, 78.503°, and 77.577°

4 0
2 years ago
How to find standard deviation from percentile for normal distribution?
QveST [7]
The standard deviation of what?  Percentiles from any normal distribution look the same, just like the unit normal, so you can't really determine the standard deviation of the original scores. You can determine a z score from a percentile.  That tells us the number of standard deviations, positive or negative, a given score is away from the mean score.  It's a normalized test result.

Your percentile is (a hundred times) the probability that another score is less than your score.  We have a normal distribution, so that probability is the integral of the standard normal from negative infinity to our normalized score.  

Let's call the percentile rank p, already scaled between zero and 1.

p=.5 corresponds to a z score z=0 because the fiftieth percentile means we got an exactly average score, 0 standard deviations away from the mean.

We know 68% of the probability will be between -1 and +1 standard deviation.  So z=-1 corresponds to p=.5-.68/2=.16 and
z=1 corresponds to p=.5+.68/2=.84

Similarly, 95% of the probability will be between -2 and +2 standard deviations.  So z=-2 corresponds to p=.5-.95/2=.025 and
z=2 corresponds to p=.5+.95/2=.975

That's about the list I can do off the top of my head. I think three standard deviations is 99.7%. For the rest we just consult a z table or integrated normal table.  We find p in the body of the table (maybe |.5-p| depending on the table) and then the column headings tell us our z score.

In this modern age, your computer can do this for you quickly

8 0
3 years ago
A rectangle is 3 1/3 ft long and 2 1/3 feet wide. What is the distance around the rectangle?
Sonja [21]
3 1/3= 10/3
2 1/3= 7/3
7/3 + 10/3= 17/3
17/3 (2)+ 34/3
34/3= 11 1/3
final answer = 11 1/3
8 0
3 years ago
Read 2 more answers
Angle ABC is inscribed in a circle as shown.<br><br>What is the measure, in degrees, of angle ABC?
sladkih [1.3K]

Answer

Find out the measure, in degrees, of angle ABC .

To prove

The relationship between inscribed angles and their arcs

The measure of an inscribed angle is half the measure the intercepted arc.

The formula is  

Measure\ of\ inscribed\ angle = \frac{1}{2}\times measure\ of\ intercepted\ arc

As given in the diagram

The measure of the intercepted arc A to B is 120°.

Put value in the formula

\angle ABC = \frac{1\times 120^{\circ}}{2}

∠ABC = 60°

Therefore the measure of the ∠ABC is 60° .


5 0
3 years ago
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