Which number is not a solution to the inequality below? x<15 A -6 B -2 C 11 D 17 Please help! Thanks
1 answer:
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Answer:
a. y-intercept = 23350 and x-intercept = 13
b.
c.
Step-by-step explanation:
Given
Solving (a): The x and y intercepts
The y intercept is the initial depreciation value
i.e. when x = 0
This value is the value of the car when it was initially purchased.
Hence, the y-intercept = 23350
The x intercept is the year it takes to finish depreciating
i.e. when y = 0
From the question, we understand that it takes 13 years for the car to totally get depreciated.
Hence, the x-intercept = 13
Solving (b): The slope
The slope (m) is the rate of depreciation per year
This is calculated by dividing the total depreciation by the duration.
So:
Because it is depreciation, it means the slope represents a deduction.
So,
Solving (c): The straight line equation
The general format of an equation is:
Where
In (a), we have that:
In (b), we have that:
Substitute these values in
<em>Hence, the depreciation equation is: </em><em></em>
Answer:
Step-by-step explanation:
<u><em>The complete question is</em></u>
A chef bought $17.01 worth of ribs and chicken. Ribs cost 1.89 per pound and chicken costs 0.90 per pound. The equation 0.90 +1.89r = 17.01 represents the relationship between the quantities in this situation.
Show that each of the following equations is equivalent to 0.9c + 1.89r = 17.01.
Then, explain when it might be helpful to write the equation in these forms.
a. c=18.9-2.1r. b. r= -10÷2c+9
we have that
The linear equation in standard form is
where
c is the pounds of chicken
r is the pounds of ribs
step 1
Solve the equation for c
That means ----> isolate the variable c
Subtract 1.89r both sides
Divide by 0.90 both sides
Simplify
step 2
Solve the equation for r
That means ----> isolate the variable r
Subtract 0.90c both sides
Divide by 1.89 both sides
Simplify
therefore
The equation is equivalent
The equation is helpful, because if I want to know the number of pounds of chicken, I just need to substitute the number of pounds of ribs in the equation to get the result.