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3 years ago

8

Ryan is taking a survey to find out how many people prefer soda A over soda B. He surveyed 100 people and forty-nine preferred s

oda A. Seven percent had no preference for soda A or soda B. What percentage of peoples surveyed preferred soda B?

1 answer:

marysya [2.9K]3 years ago

8 0

Answer:

44%

Step-by-step explanation:

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Evaluate the polynomial function when H=3<br> f(h)=4h^3-3h^2+5h-16

tester [92]

Answer:

80

Step-by-step explanation:

f(3)=4(3)^3-3(3)^2+5(3)-16

f(3)=4(3*3*3)-3(3*3)+15-16

f(3)=4(27)-3(9)+15-16

f(3)=108-27+15-16

f(3)=81+15-16

f(3)=96-16

f(3)=80

8 0

3 years ago

5 is what percent of 20

Alenkasestr [34]

It is one fourth of twenty so therefor 5 is 25% of 20

4 0

3 years ago

Points L, M, and N are collinear.

Natali5045456 [20]

<h3>Answer:</h3>

33

<h3>Step-by-step explanation:</h3>

Vocabulary

Before going into an explanation, let's go over some important vocabulary.

Collinear - Collinear describes points that are on the same line. This means that there is 1 line with the 3 points L, M, and N.
Segment addition postulate - The segment addition postulate states that if there are 2 collinear points (A and C) with another point in between them (B), then the statement AB + BC = AC must be true.

Solving for MN

Using the postulate above we can make a new equation. First, let's set up an equation that mirrors the postulate.

LM + LN = MN

Now, let's plug in the values we know.

13 + 20 = MN

Then, solve.

33 = MN

This proves that a possible value of MN is 33.

6 0

2 years ago

Can you help me with the bottom three please?

nika2105 [10]

Answer:

6= 66.67%

7=25%

8=70%

6 0

4 years ago

Write the equation of a line that is perpendicular to the given line and that passes through the given point.

katrin2010 [14]

Greetings and Happy Holidays!

<span>1) Perpendicular to </span> $-x+5y=14$
In order for lines to be perpendicular, their slopes must be negative reciprocals.
Example of slopes with negative reciprocals: 5 and $\frac{-1}{5}$

First, rearrange the equation into slope y-intercept form:
$-x+5y=14$

$5y=x+14$

$\frac{5y}{5}=\frac{x+14}{5}$

$y=\frac{1}{5}x+\frac{14}{5}$

The slope of the equation is: \frac{1}{5}

The negative reciprocal formula: $(m_{1})(m_{2})=-1$

Solve for the negative reciprocal:
$\frac{1}{5}m_{2}=-1$

Divide both sides by $\frac{1}{5}$
$\frac{\frac{1}{5}m_{2} }{ \frac{1}{5}} = \frac{-1}{ \frac{1}{5}}$

$m_{2}=(-1)(\frac{5}{1})$

$m_{2}=(\frac{-5}{1})$

$m_{2}=-5$

The slope of the new line is: -5

2) Passes through (-5,-2)

Create an equation with the slope discovered in slope y-intercept form.
$y=-5x+b$

Input the point the line passes through.
$(-2)=-5(-5)+b$

Solve for b (the y-intercept).
$-2=-5(-5)+b$

Multiply.
$-2=25+b$

Add -25 to both sides.
$(-2)+(-25)=b$

$-27=b$

The y-intercept is equal to -27

The Equation of the line is:
$y=-5x-27$

I hope this helped!
-Benjamin

6 0

4 years ago